JEE Advanced Chapter-Wise Previous Year Questions (PYQ) Practice

Q1Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Rotational Motion & Rigid Body Dynamics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 1 Physics Q1] A thin uniform circular disc of mass

M

and radius

R

is placed on a rough horizontal surface with coefficient of friction

\mu

. At time

t=0

, a horizontal impulse

J

is applied at a height

h = \frac{R}{2}

above the center of mass. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Rotational Motion & Rigid Body Dynamics)

Q2Paper 1PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrostatics & Electric Potential

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 1 Physics Q2] A point charge

+q

is located at a distance

d

from the planar boundary of an infinite semi-infinite dielectric medium with dielectric constant

K > 1

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Electrostatics & Electric Potential)

Q3Paper 1PhysicsSingle Correct OptionHard

Thermodynamics & Kinetic Theory

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 1 Physics Q3] One mole of an ideal gas has a molar heat capacity at constant volume that varies with absolute temperature according to

C_V = C_0 + \alpha T

, where

C_0

and

\alpha

are positive constants. The gas undergoes a quasi-static adiabatic process from initial state

(T_1, V_1)

to final state

(T_2, V_2)

. The relation between

T

and

V

is given by:

Practice JEE Main Level (Thermodynamics & Kinetic Theory)

Q4Paper 1PhysicsNumerical Value TypeTough / Advanced

Electromagnetic Induction & Alternating Current

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 1 Physics Q4] A circular wire loop of radius

a = 0.1\text{ m}

and resistance

R = 2\,\Omega

is placed in a uniform magnetic field

B(t) = B_0 \cos(\omega t)

directed perpendicular to the loop, where

B_0 = 1\text{ T}

and

\omega = 100\text{ rad/s}

. If self-inductance of the loop is

L = 0.02\text{ H}

, find the peak magnitude of current (in Amperes) induced in the loop. (Take

\pi \approx 3.14

, calculate to two decimal places).

Practice JEE Main Level (Electromagnetic Induction & Alternating Current)

Q5Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Wave Optics & Interference

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 1 Physics Q5] In a standard YDSE setup with slit separation

d

and screen distance

D

, a transparent thin film of thickness

t

is placed in front of one slit. The refractive index of the film varies along its thickness

y

as

\mu(y) = \mu_0 + \beta y

for

0 \le y \le t

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Wave Optics & Interference)

Q6Paper 1PhysicsSingle Correct OptionHard

Modern Physics & Quantum Mechanics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 1 Physics Q6] A hydrogen-like atom consists of a nucleus of mass

M

and charge

+Z e

and an electron of mass

m_e

and charge

-e

. Taking finite nuclear mass into account via reduced mass

\mu = \frac{m_e M}{m_e + M}

, the Rydberg constant

R_M

for this atom is related to the infinite nuclear mass Rydberg constant

R_\infty

by:

Practice JEE Main Level (Modern Physics & Quantum Mechanics)

Q7Paper 1PhysicsNumerical Value TypeTough / Advanced

Fluid Mechanics & Surface Tension

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 1 Physics Q7] A clean glass capillary tube of internal radius

r = 0.5\text{ mm}

is dipped vertically into water of surface tension

T = 0.075\text{ N/m}

, contact angle

\theta = 0^\circ

, and density

\rho = 1000\text{ kg/m}^3

. What is the equilibrium height

h

(in mm) of the water column in the capillary tube? (Take

g = 10\text{ m/s}^2

).

Practice JEE Main Level (Fluid Mechanics & Surface Tension)

Q8Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Mechanics & Gravitation

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 1 Physics Q8] A physical system operating under Mechanics & Gravitation is analyzed for Kepler Orbit & Angular Momentum in Elliptical Trajectory. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Mechanics & Gravitation)

Q9Paper 1PhysicsOne or More Correct (Partial Marking)Medium

Oscillations & SHM

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 1 Physics Q9] A physical system operating under Oscillations & SHM is analyzed for Coupled Spring Mass System & Normal Modes. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Oscillations & SHM)

Q10Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Magnetic Effects of Current

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 1 Physics Q10] A physical system operating under Magnetic Effects of Current is analyzed for Cyclotron Motion in Crossed Electric and Magnetic Fields. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Magnetic Effects of Current)

Q11Paper 1PhysicsNumerical Value TypeMedium

Ray Optics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 1 Physics Q11] A physical system operating under Ray Optics is analyzed for Refraction through Silvered Prism & Dispersion without Deviation. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Ray Optics)

Q12Paper 1PhysicsNumerical Value TypeHard

Alternating Current

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 1 Physics Q12] A physical system operating under Alternating Current is analyzed for LCR Resonance & Quality Factor Sharpness. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Alternating Current)

Q13Paper 1PhysicsNumerical Value TypeMedium

Semiconductors

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 1 Physics Q13] A physical system operating under Semiconductors is analyzed for Zener Diode Voltage Regulator with Variable Load. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Semiconductors)

Q14Paper 1PhysicsNumerical Value TypeHard

Nuclear Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 1 Physics Q14] A physical system operating under Nuclear Physics is analyzed for Successive Radioactive Decay & Secular Equilibrium. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Nuclear Physics)

Q15Paper 1PhysicsSingle Correct OptionMedium

Wave Motion

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 1 Physics Q15] A physical system operating under Wave Motion is analyzed for Doppler Effect with Reflected Echo from Moving Reflector. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Wave Motion)

Q16Paper 1PhysicsSingle Correct OptionHard

Work Energy Power

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 1 Physics Q16] A physical system operating under Work Energy Power is analyzed for Vertical Circular Motion with Critical Tension at Zenith. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Work Energy Power)

Q17Paper 1PhysicsSingle Correct OptionMedium

Kinematics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 1 Physics Q17] A physical system operating under Kinematics is analyzed for Relative Motion in 2D River Swimmer Shortest Time vs Shortest Path. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Kinematics)

Q18Paper 1Chemistry (Physical)Single Correct OptionMedium

Coordination Compounds & Qualitative Inorganic Analysis

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 1 Chemistry Q18] Among the following octahedral coordination complexes, which one exhibits the highest crystal field stabilization energy (CFSE) in terms of magnitude of

\Delta_o

and possesses zero unpaired electrons (

n=0

)?

Practice JEE Main Level (Coordination Compounds & Qualitative Inorganic Analysis)

Q19Paper 1Chemistry (Inorganic)One or More Correct (Partial Marking)Hard

Organic Chemistry & Reaction Mechanisms

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 1 Chemistry Q19] Treatment of 2,3-dimethylbutane-2,3-diol (Pinacol) with concentrated sulphuric acid (

H_2SO_4

) at elevated temperature yields 3,3-dimethylbutan-2-one (Pinacolone). Which of the following statements concerning this reaction is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Organic Chemistry & Reaction Mechanisms)

Q20Paper 1Chemistry (Organic)One or More Correct (Partial Marking)Hard

Chemical Kinetics & Radioactivity

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 1 Chemistry Q20] In a detailed investigation of Consecutive First Order Reactions & Steady State Approximation under Chemical Kinetics & Radioactivity, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Chemical Kinetics & Radioactivity)

Q21Paper 1Chemistry (Physical)One or More Correct (Partial Marking)Medium

Thermodynamics & Thermochemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 1 Chemistry Q21] In a detailed investigation of Born-Haber Cycle & Lattice Energy Calculations under Thermodynamics & Thermochemistry, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Thermodynamics & Thermochemistry)

Q22Paper 1Chemistry (Organic)One or More Correct (Partial Marking)Hard

Electrochemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 1 Chemistry Q22] In a detailed investigation of Concentration Cell with Transference & Liquid Junction Potential under Electrochemistry, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Electrochemistry)

Q23Paper 1Chemistry (Inorganic)One or More Correct (Partial Marking)Medium

Chemical & Ionic Equilibrium

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 1 Chemistry Q23] In a detailed investigation of Simultaneous Solubility in Amphoteric Hydroxide Solutions under Chemical & Ionic Equilibrium, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Chemical & Ionic Equilibrium)

Q24Paper 1Chemistry (Physical)One or More Correct (Partial Marking)Hard

Solid State

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 1 Chemistry Q24] In a detailed investigation of Radius Ratio & Octahedral vs Tetrahedral Void Occupancy under Solid State, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Solid State)

Q25Paper 1Chemistry (Inorganic)Numerical Value TypeMedium

Solutions & Colligative Properties

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 1 Chemistry Q25] In a detailed investigation of Van't Hoff Factor in Dimerization and Association Equilibria under Solutions & Colligative Properties, consider the reacting mixture and mechanism:

Practice JEE Main Level (Solutions & Colligative Properties)

Q26Paper 1Chemistry (Organic)Numerical Value TypeHard

p-Block Elements

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 1 Chemistry Q26] In a detailed investigation of Oxyacids of Phosphorus & Silicon Polymers Structure under p-Block Elements, consider the reacting mixture and mechanism:

Practice JEE Main Level (p-Block Elements)

Q27Paper 1Chemistry (Physical)Numerical Value TypeMedium

d- and f-Block Elements

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 1 Chemistry Q27] In a detailed investigation of Lanthanoid Contraction & Separation of Rare Earth Ions under d- and f-Block Elements, consider the reacting mixture and mechanism:

Practice JEE Main Level (d- and f-Block Elements)

Q28Paper 1Chemistry (Organic)Numerical Value TypeHard

Metallurgy & Extraction

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 1 Chemistry Q28] In a detailed investigation of Ellingham Diagram & Thermodynamic Feasibility of Smelting under Metallurgy & Extraction, consider the reacting mixture and mechanism:

Practice JEE Main Level (Metallurgy & Extraction)

Q29Paper 1Chemistry (Inorganic)Numerical Value TypeMedium

Aldehydes, Ketones and Carboxylic Acids

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 1 Chemistry Q29] In a detailed investigation of Intramolecular Aldol & Michael Addition Sequence under Aldehydes, Ketones and Carboxylic Acids, consider the reacting mixture and mechanism:

Practice JEE Main Level (Aldehydes, Ketones and Carboxylic Acids)

Q30Paper 1Chemistry (Physical)Single Correct OptionHard

Aromatic Compounds

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 1 Chemistry Q30] In a detailed investigation of Electrophilic Aromatic Substitution with Directing Groups under Aromatic Compounds, consider the reacting mixture and mechanism:

Practice JEE Main Level (Aromatic Compounds)

Q31Paper 1Chemistry (Inorganic)Single Correct OptionMedium

Amines & Diazonium Salts

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 1 Chemistry Q31] In a detailed investigation of Sandmeyer Reaction vs Gattermann Synthesis Mechanisms under Amines & Diazonium Salts, consider the reacting mixture and mechanism:

Practice JEE Main Level (Amines & Diazonium Salts)

Q32Paper 1Chemistry (Organic)Single Correct OptionHard

Biomolecules & Polymers

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 1 Chemistry Q32] In a detailed investigation of Mutarotation in Glucose & Peptide Linkage Conformation under Biomolecules & Polymers, consider the reacting mixture and mechanism:

Practice JEE Main Level (Biomolecules & Polymers)

Q33Paper 1Chemistry (Physical)Single Correct OptionMedium

Haloalkanes & Haloarenes

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 1 Chemistry Q33] In a detailed investigation of SN1 vs SN2 vs SNi Mechanisms with Stereochemical Inversion under Haloalkanes & Haloarenes, consider the reacting mixture and mechanism:

Practice JEE Main Level (Haloalkanes & Haloarenes)

Q34Paper 1Chemistry (Organic)Single Correct OptionHard

Qualitative Inorganic Salt Analysis

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 1 Chemistry Q34] In a detailed investigation of Chromyl Chloride Test & Brown Ring Complex Formation under Qualitative Inorganic Salt Analysis, consider the reacting mixture and mechanism:

Practice JEE Main Level (Qualitative Inorganic Salt Analysis)

Q35Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Integral Calculus (Definite Integrals & Differential Equations)

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 1 Mathematics Q35] Let

f: (0, \infty) \to \mathbb{R}

be a differentiable function satisfying

f(1) = 1

and

x \int_1^x f(t) dt = (x+1) \int_1^x t f(t) dt

for all

x > 0

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Integral Calculus (Definite Integrals & Differential Equations))

Q36Paper 1MathematicsNumerical Value TypeMedium

Vectors and 3D Geometry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 1 Mathematics Q36] Find the shortest distance between the two skew straight lines

L_1: \vec{r}_1 = (\hat{i} + 2\hat{j} + 3\hat{k}) + \lambda (2\hat{i} + 3\hat{j} + 4\hat{k})

and

L_2: \vec{r}_2 = (2\hat{i} + 4\hat{j} + 5\hat{k}) + \mu (3\hat{i} + 4\hat{j} + 5\hat{k})

. Give the exact distance squared (

d^2

).

Practice JEE Main Level (Vectors and 3D Geometry)

Q37Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Complex Numbers & Quadratic Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 1 Mathematics Q37] Let the mathematical relation governing Geometry of Circles and Apollonius Circles in Complex Plane in Complex Numbers & Quadratic Equations be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Complex Numbers & Quadratic Equations)

Q38Paper 1MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Matrices and Determinants

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 1 Mathematics Q38] Let the mathematical relation governing Cayley-Hamilton Theorem and Inverse of Orthogonal Matrices in Matrices and Determinants be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Matrices and Determinants)

Q39Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Probability & Statistics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 1 Mathematics Q39] Let the mathematical relation governing Bayes Theorem in Multi-Urn Sampling with Replacement in Probability & Statistics be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Probability & Statistics)

Q40Paper 1MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Permutations and Combinations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 1 Mathematics Q40] Let the mathematical relation governing Derangements and Multinomial Distribution Coefficients in Permutations and Combinations be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Permutations and Combinations)

Q41Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Differential Calculus (Continuity & AOD)

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 1 Mathematics Q41] Let the mathematical relation governing Lagrange Mean Value Theorem and Monotonicity Intervals in Differential Calculus (Continuity & AOD) be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Differential Calculus (Continuity & AOD))

Q42Paper 1MathematicsNumerical Value TypeTough / Advanced

Application of Derivatives (Maxima & Minima)

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 1 Mathematics Q42] Let the mathematical relation governing Optimization on Parametric Curves with Constraint Geometry in Application of Derivatives (Maxima & Minima) be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Application of Derivatives (Maxima & Minima))

Q43Paper 1MathematicsNumerical Value TypeHard

Definite Integration

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 1 Mathematics Q43] Let the mathematical relation governing King Rule and Reduction Formula for Trigonometric Powers in Definite Integration be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Definite Integration)

Q44Paper 1MathematicsNumerical Value TypeTough / Advanced

Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 1 Mathematics Q44] Let the mathematical relation governing Bernoulli Differential Equation with Variable Substitution in Differential Equations be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Differential Equations)

Q45Paper 1MathematicsNumerical Value TypeHard

Coordinate Geometry - Parabola

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 1 Mathematics Q45] Let the mathematical relation governing Co-normal Points and Locus of Point of Intersection of Tangents in Coordinate Geometry - Parabola be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Coordinate Geometry - Parabola)

Q46Paper 1MathematicsNumerical Value TypeTough / Advanced

Coordinate Geometry - Ellipse & Hyperbola

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 1 Mathematics Q46] Let the mathematical relation governing Director Circle and Asymptotes of Conjugate Hyperbolas in Coordinate Geometry - Ellipse & Hyperbola be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Coordinate Geometry - Ellipse & Hyperbola)

Q47Paper 1MathematicsSingle Correct OptionHard

Trigonometry & Inverse Trigonometric Functions

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 1 Mathematics Q47] Let the mathematical relation governing Summation of Inverse Trigonometric Series via Telescoping in Trigonometry & Inverse Trigonometric Functions be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Trigonometry & Inverse Trigonometric Functions)

Q48Paper 1MathematicsSingle Correct OptionTough / Advanced

Binomial Theorem

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 1 Mathematics Q48] Let the mathematical relation governing Double Summation and Coefficients of Generalized Multinomial Series in Binomial Theorem be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Binomial Theorem)

Q49Paper 1MathematicsSingle Correct OptionHard

Limits, Continuity and Differentiability

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 1 Mathematics Q49] Let the mathematical relation governing Evaluation of

1^\infty

Indeterminate Form and Squeeze Theorem in Limits, Continuity and Differentiability be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Limits, Continuity and Differentiability)

Q50Paper 1MathematicsSingle Correct OptionTough / Advanced

Functions & Relations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 1 Mathematics Q50] Let the mathematical relation governing Functional Equations and Injective/Surjective Mapping Properties in Functions & Relations be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Functions & Relations)

Q51Paper 1MathematicsSingle Correct OptionHard

Sequences and Series

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 1 Mathematics Q51] Let the mathematical relation governing Arithmetico-Geometric Progression (AGP) and Infinite Sum Convergence in Sequences and Series be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Sequences and Series)

Q1Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 2 Physics Q1] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 2

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q2Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 2 Physics Q2] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 4

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q3Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 2 Physics Q3] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 6

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q4Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 2 Physics Q4] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 8

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q5Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 2 Physics Q5] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 10

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q6Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 2 Physics Q6] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 12

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q7Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 2 Physics Q7] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 14

. Find the exact response:

Q8Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 2 Physics Q8] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 16

. Find the exact response:

Q9Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 2 Physics Q9] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 18

. Find the exact response:

Q10Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 2 Physics Q10] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 20

. Find the exact response:

Q11Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 2 Physics Q11] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 22

. Find the exact response:

Q12Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 2 Physics Q12] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 24

. Find the exact response:

Q13Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 2 Physics Q13] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 26

. Find the exact response:

Q14Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 2 Physics Q14] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 28

. Find the exact response:

Q15Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 2 Physics Q15] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 30

. Find the exact response:

Q16Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 2 Physics Q16] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 32

. Find the exact response:

Q17Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 2 Physics Q17] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 34

. Find the exact response:

Q18Paper 2Chemistry (Physical)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 2 Chemistry Q18] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q19Paper 2Chemistry (Inorganic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 2 Chemistry Q19] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q20Paper 2Chemistry (Organic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 2 Chemistry Q20] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q21Paper 2Chemistry (Physical)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 2 Chemistry Q21] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q22Paper 2Chemistry (Organic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 2 Chemistry Q22] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q23Paper 2Chemistry (Inorganic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 2 Chemistry Q23] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q24Paper 2Chemistry (Physical)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 2 Chemistry Q24] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q25Paper 2Chemistry (Inorganic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 2 Chemistry Q25] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q26Paper 2Chemistry (Organic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 2 Chemistry Q26] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q27Paper 2Chemistry (Physical)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 2 Chemistry Q27] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q28Paper 2Chemistry (Organic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 2 Chemistry Q28] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q29Paper 2Chemistry (Inorganic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 2 Chemistry Q29] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q30Paper 2Chemistry (Physical)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 2 Chemistry Q30] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q31Paper 2Chemistry (Inorganic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 2 Chemistry Q31] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q32Paper 2Chemistry (Organic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 2 Chemistry Q32] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q33Paper 2Chemistry (Physical)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 2 Chemistry Q33] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q34Paper 2Chemistry (Organic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 2 Chemistry Q34] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q35Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 2 Mathematics Q35] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q36Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 2 Mathematics Q36] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q37Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 2 Mathematics Q37] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q38Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 2 Mathematics Q38] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q39Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 2 Mathematics Q39] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q40Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2025 Paper 2 Mathematics Q40] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q41Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 2 Mathematics Q41] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q42Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 2 Mathematics Q42] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q43Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 2 Mathematics Q43] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q44Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 2 Mathematics Q44] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q45Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 2 Mathematics Q45] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q46Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2025 Paper 2 Mathematics Q46] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q47Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 2 Mathematics Q47] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q48Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 2 Mathematics Q48] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q49Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 2 Mathematics Q49] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q50Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 2 Mathematics Q50] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q51Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2025 Paper 2 Mathematics Q51] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q1Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Rotational Motion & Rigid Body Dynamics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 1 Physics Q1] A thin uniform circular disc of mass

M

and radius

R

is placed on a rough horizontal surface with coefficient of friction

\mu

. At time

t=0

, a horizontal impulse

J

is applied at a height

h = \frac{R}{2}

above the center of mass. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Rotational Motion & Rigid Body Dynamics)

Q2Paper 1PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrostatics & Electric Potential

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 1 Physics Q2] A point charge

+q

is located at a distance

d

from the planar boundary of an infinite semi-infinite dielectric medium with dielectric constant

K > 1

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Electrostatics & Electric Potential)

Q3Paper 1PhysicsSingle Correct OptionHard

Thermodynamics & Kinetic Theory

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 1 Physics Q3] One mole of an ideal gas has a molar heat capacity at constant volume that varies with absolute temperature according to

C_V = C_0 + \alpha T

, where

C_0

and

\alpha

are positive constants. The gas undergoes a quasi-static adiabatic process from initial state

(T_1, V_1)

to final state

(T_2, V_2)

. The relation between

T

and

V

is given by:

Practice JEE Main Level (Thermodynamics & Kinetic Theory)

Q4Paper 1PhysicsNumerical Value TypeTough / Advanced

Electromagnetic Induction & Alternating Current

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 1 Physics Q4] A circular wire loop of radius

a = 0.1\text{ m}

and resistance

R = 2\,\Omega

is placed in a uniform magnetic field

B(t) = B_0 \cos(\omega t)

directed perpendicular to the loop, where

B_0 = 1\text{ T}

and

\omega = 100\text{ rad/s}

. If self-inductance of the loop is

L = 0.02\text{ H}

, find the peak magnitude of current (in Amperes) induced in the loop. (Take

\pi \approx 3.14

, calculate to two decimal places).

Practice JEE Main Level (Electromagnetic Induction & Alternating Current)

Q5Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Wave Optics & Interference

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 1 Physics Q5] In a standard YDSE setup with slit separation

d

and screen distance

D

, a transparent thin film of thickness

t

is placed in front of one slit. The refractive index of the film varies along its thickness

y

as

\mu(y) = \mu_0 + \beta y

for

0 \le y \le t

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Wave Optics & Interference)

Q6Paper 1PhysicsSingle Correct OptionHard

Modern Physics & Quantum Mechanics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 1 Physics Q6] A hydrogen-like atom consists of a nucleus of mass

M

and charge

+Z e

and an electron of mass

m_e

and charge

-e

. Taking finite nuclear mass into account via reduced mass

\mu = \frac{m_e M}{m_e + M}

, the Rydberg constant

R_M

for this atom is related to the infinite nuclear mass Rydberg constant

R_\infty

by:

Practice JEE Main Level (Modern Physics & Quantum Mechanics)

Q7Paper 1PhysicsNumerical Value TypeTough / Advanced

Fluid Mechanics & Surface Tension

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 1 Physics Q7] A clean glass capillary tube of internal radius

r = 0.5\text{ mm}

is dipped vertically into water of surface tension

T = 0.075\text{ N/m}

, contact angle

\theta = 0^\circ

, and density

\rho = 1000\text{ kg/m}^3

. What is the equilibrium height

h

(in mm) of the water column in the capillary tube? (Take

g = 10\text{ m/s}^2

).

Practice JEE Main Level (Fluid Mechanics & Surface Tension)

Q8Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Mechanics & Gravitation

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 1 Physics Q8] A physical system operating under Mechanics & Gravitation is analyzed for Kepler Orbit & Angular Momentum in Elliptical Trajectory. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Mechanics & Gravitation)

Q9Paper 1PhysicsOne or More Correct (Partial Marking)Medium

Oscillations & SHM

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 1 Physics Q9] A physical system operating under Oscillations & SHM is analyzed for Coupled Spring Mass System & Normal Modes. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Oscillations & SHM)

Q10Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Magnetic Effects of Current

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 1 Physics Q10] A physical system operating under Magnetic Effects of Current is analyzed for Cyclotron Motion in Crossed Electric and Magnetic Fields. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Magnetic Effects of Current)

Q11Paper 1PhysicsNumerical Value TypeMedium

Ray Optics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 1 Physics Q11] A physical system operating under Ray Optics is analyzed for Refraction through Silvered Prism & Dispersion without Deviation. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Ray Optics)

Q12Paper 1PhysicsNumerical Value TypeHard

Alternating Current

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 1 Physics Q12] A physical system operating under Alternating Current is analyzed for LCR Resonance & Quality Factor Sharpness. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Alternating Current)

Q13Paper 1PhysicsNumerical Value TypeMedium

Semiconductors

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 1 Physics Q13] A physical system operating under Semiconductors is analyzed for Zener Diode Voltage Regulator with Variable Load. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Semiconductors)

Q14Paper 1PhysicsNumerical Value TypeHard

Nuclear Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 1 Physics Q14] A physical system operating under Nuclear Physics is analyzed for Successive Radioactive Decay & Secular Equilibrium. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Nuclear Physics)

Q15Paper 1PhysicsSingle Correct OptionMedium

Wave Motion

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 1 Physics Q15] A physical system operating under Wave Motion is analyzed for Doppler Effect with Reflected Echo from Moving Reflector. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Wave Motion)

Q16Paper 1PhysicsSingle Correct OptionHard

Work Energy Power

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 1 Physics Q16] A physical system operating under Work Energy Power is analyzed for Vertical Circular Motion with Critical Tension at Zenith. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Work Energy Power)

Q17Paper 1PhysicsSingle Correct OptionMedium

Kinematics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 1 Physics Q17] A physical system operating under Kinematics is analyzed for Relative Motion in 2D River Swimmer Shortest Time vs Shortest Path. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Kinematics)

Q18Paper 1Chemistry (Physical)Single Correct OptionMedium

Coordination Compounds & Qualitative Inorganic Analysis

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 1 Chemistry Q18] Among the following octahedral coordination complexes, which one exhibits the highest crystal field stabilization energy (CFSE) in terms of magnitude of

\Delta_o

and possesses zero unpaired electrons (

n=0

)?

Practice JEE Main Level (Coordination Compounds & Qualitative Inorganic Analysis)

Q19Paper 1Chemistry (Inorganic)One or More Correct (Partial Marking)Hard

Organic Chemistry & Reaction Mechanisms

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 1 Chemistry Q19] Treatment of 2,3-dimethylbutane-2,3-diol (Pinacol) with concentrated sulphuric acid (

H_2SO_4

) at elevated temperature yields 3,3-dimethylbutan-2-one (Pinacolone). Which of the following statements concerning this reaction is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Organic Chemistry & Reaction Mechanisms)

Q20Paper 1Chemistry (Organic)One or More Correct (Partial Marking)Hard

Chemical Kinetics & Radioactivity

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 1 Chemistry Q20] In a detailed investigation of Consecutive First Order Reactions & Steady State Approximation under Chemical Kinetics & Radioactivity, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Chemical Kinetics & Radioactivity)

Q21Paper 1Chemistry (Physical)One or More Correct (Partial Marking)Medium

Thermodynamics & Thermochemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 1 Chemistry Q21] In a detailed investigation of Born-Haber Cycle & Lattice Energy Calculations under Thermodynamics & Thermochemistry, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Thermodynamics & Thermochemistry)

Q22Paper 1Chemistry (Organic)One or More Correct (Partial Marking)Hard

Electrochemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 1 Chemistry Q22] In a detailed investigation of Concentration Cell with Transference & Liquid Junction Potential under Electrochemistry, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Electrochemistry)

Q23Paper 1Chemistry (Inorganic)One or More Correct (Partial Marking)Medium

Chemical & Ionic Equilibrium

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 1 Chemistry Q23] In a detailed investigation of Simultaneous Solubility in Amphoteric Hydroxide Solutions under Chemical & Ionic Equilibrium, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Chemical & Ionic Equilibrium)

Q24Paper 1Chemistry (Physical)One or More Correct (Partial Marking)Hard

Solid State

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 1 Chemistry Q24] In a detailed investigation of Radius Ratio & Octahedral vs Tetrahedral Void Occupancy under Solid State, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Solid State)

Q25Paper 1Chemistry (Inorganic)Numerical Value TypeMedium

Solutions & Colligative Properties

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 1 Chemistry Q25] In a detailed investigation of Van't Hoff Factor in Dimerization and Association Equilibria under Solutions & Colligative Properties, consider the reacting mixture and mechanism:

Practice JEE Main Level (Solutions & Colligative Properties)

Q26Paper 1Chemistry (Organic)Numerical Value TypeHard

p-Block Elements

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 1 Chemistry Q26] In a detailed investigation of Oxyacids of Phosphorus & Silicon Polymers Structure under p-Block Elements, consider the reacting mixture and mechanism:

Practice JEE Main Level (p-Block Elements)

Q27Paper 1Chemistry (Physical)Numerical Value TypeMedium

d- and f-Block Elements

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 1 Chemistry Q27] In a detailed investigation of Lanthanoid Contraction & Separation of Rare Earth Ions under d- and f-Block Elements, consider the reacting mixture and mechanism:

Practice JEE Main Level (d- and f-Block Elements)

Q28Paper 1Chemistry (Organic)Numerical Value TypeHard

Metallurgy & Extraction

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 1 Chemistry Q28] In a detailed investigation of Ellingham Diagram & Thermodynamic Feasibility of Smelting under Metallurgy & Extraction, consider the reacting mixture and mechanism:

Practice JEE Main Level (Metallurgy & Extraction)

Q29Paper 1Chemistry (Inorganic)Numerical Value TypeMedium

Aldehydes, Ketones and Carboxylic Acids

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 1 Chemistry Q29] In a detailed investigation of Intramolecular Aldol & Michael Addition Sequence under Aldehydes, Ketones and Carboxylic Acids, consider the reacting mixture and mechanism:

Practice JEE Main Level (Aldehydes, Ketones and Carboxylic Acids)

Q30Paper 1Chemistry (Physical)Single Correct OptionHard

Aromatic Compounds

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 1 Chemistry Q30] In a detailed investigation of Electrophilic Aromatic Substitution with Directing Groups under Aromatic Compounds, consider the reacting mixture and mechanism:

Practice JEE Main Level (Aromatic Compounds)

Q31Paper 1Chemistry (Inorganic)Single Correct OptionMedium

Amines & Diazonium Salts

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 1 Chemistry Q31] In a detailed investigation of Sandmeyer Reaction vs Gattermann Synthesis Mechanisms under Amines & Diazonium Salts, consider the reacting mixture and mechanism:

Practice JEE Main Level (Amines & Diazonium Salts)

Q32Paper 1Chemistry (Organic)Single Correct OptionHard

Biomolecules & Polymers

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 1 Chemistry Q32] In a detailed investigation of Mutarotation in Glucose & Peptide Linkage Conformation under Biomolecules & Polymers, consider the reacting mixture and mechanism:

Practice JEE Main Level (Biomolecules & Polymers)

Q33Paper 1Chemistry (Physical)Single Correct OptionMedium

Haloalkanes & Haloarenes

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 1 Chemistry Q33] In a detailed investigation of SN1 vs SN2 vs SNi Mechanisms with Stereochemical Inversion under Haloalkanes & Haloarenes, consider the reacting mixture and mechanism:

Practice JEE Main Level (Haloalkanes & Haloarenes)

Q34Paper 1Chemistry (Organic)Single Correct OptionHard

Qualitative Inorganic Salt Analysis

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 1 Chemistry Q34] In a detailed investigation of Chromyl Chloride Test & Brown Ring Complex Formation under Qualitative Inorganic Salt Analysis, consider the reacting mixture and mechanism:

Practice JEE Main Level (Qualitative Inorganic Salt Analysis)

Q35Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Integral Calculus (Definite Integrals & Differential Equations)

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 1 Mathematics Q35] Let

f: (0, \infty) \to \mathbb{R}

be a differentiable function satisfying

f(1) = 1

and

x \int_1^x f(t) dt = (x+1) \int_1^x t f(t) dt

for all

x > 0

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Integral Calculus (Definite Integrals & Differential Equations))

Q36Paper 1MathematicsNumerical Value TypeMedium

Vectors and 3D Geometry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 1 Mathematics Q36] Find the shortest distance between the two skew straight lines

L_1: \vec{r}_1 = (\hat{i} + 2\hat{j} + 3\hat{k}) + \lambda (2\hat{i} + 3\hat{j} + 4\hat{k})

and

L_2: \vec{r}_2 = (2\hat{i} + 4\hat{j} + 5\hat{k}) + \mu (3\hat{i} + 4\hat{j} + 5\hat{k})

. Give the exact distance squared (

d^2

).

Practice JEE Main Level (Vectors and 3D Geometry)

Q37Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Complex Numbers & Quadratic Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 1 Mathematics Q37] Let the mathematical relation governing Geometry of Circles and Apollonius Circles in Complex Plane in Complex Numbers & Quadratic Equations be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Complex Numbers & Quadratic Equations)

Q38Paper 1MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Matrices and Determinants

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 1 Mathematics Q38] Let the mathematical relation governing Cayley-Hamilton Theorem and Inverse of Orthogonal Matrices in Matrices and Determinants be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Matrices and Determinants)

Q39Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Probability & Statistics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 1 Mathematics Q39] Let the mathematical relation governing Bayes Theorem in Multi-Urn Sampling with Replacement in Probability & Statistics be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Probability & Statistics)

Q40Paper 1MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Permutations and Combinations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 1 Mathematics Q40] Let the mathematical relation governing Derangements and Multinomial Distribution Coefficients in Permutations and Combinations be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Permutations and Combinations)

Q41Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Differential Calculus (Continuity & AOD)

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 1 Mathematics Q41] Let the mathematical relation governing Lagrange Mean Value Theorem and Monotonicity Intervals in Differential Calculus (Continuity & AOD) be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Differential Calculus (Continuity & AOD))

Q42Paper 1MathematicsNumerical Value TypeTough / Advanced

Application of Derivatives (Maxima & Minima)

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 1 Mathematics Q42] Let the mathematical relation governing Optimization on Parametric Curves with Constraint Geometry in Application of Derivatives (Maxima & Minima) be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Application of Derivatives (Maxima & Minima))

Q43Paper 1MathematicsNumerical Value TypeHard

Definite Integration

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 1 Mathematics Q43] Let the mathematical relation governing King Rule and Reduction Formula for Trigonometric Powers in Definite Integration be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Definite Integration)

Q44Paper 1MathematicsNumerical Value TypeTough / Advanced

Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 1 Mathematics Q44] Let the mathematical relation governing Bernoulli Differential Equation with Variable Substitution in Differential Equations be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Differential Equations)

Q45Paper 1MathematicsNumerical Value TypeHard

Coordinate Geometry - Parabola

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 1 Mathematics Q45] Let the mathematical relation governing Co-normal Points and Locus of Point of Intersection of Tangents in Coordinate Geometry - Parabola be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Coordinate Geometry - Parabola)

Q46Paper 1MathematicsNumerical Value TypeTough / Advanced

Coordinate Geometry - Ellipse & Hyperbola

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 1 Mathematics Q46] Let the mathematical relation governing Director Circle and Asymptotes of Conjugate Hyperbolas in Coordinate Geometry - Ellipse & Hyperbola be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Coordinate Geometry - Ellipse & Hyperbola)

Q47Paper 1MathematicsSingle Correct OptionHard

Trigonometry & Inverse Trigonometric Functions

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 1 Mathematics Q47] Let the mathematical relation governing Summation of Inverse Trigonometric Series via Telescoping in Trigonometry & Inverse Trigonometric Functions be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Trigonometry & Inverse Trigonometric Functions)

Q48Paper 1MathematicsSingle Correct OptionTough / Advanced

Binomial Theorem

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 1 Mathematics Q48] Let the mathematical relation governing Double Summation and Coefficients of Generalized Multinomial Series in Binomial Theorem be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Binomial Theorem)

Q49Paper 1MathematicsSingle Correct OptionHard

Limits, Continuity and Differentiability

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 1 Mathematics Q49] Let the mathematical relation governing Evaluation of

1^\infty

Indeterminate Form and Squeeze Theorem in Limits, Continuity and Differentiability be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Limits, Continuity and Differentiability)

Q50Paper 1MathematicsSingle Correct OptionTough / Advanced

Functions & Relations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 1 Mathematics Q50] Let the mathematical relation governing Functional Equations and Injective/Surjective Mapping Properties in Functions & Relations be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Functions & Relations)

Q51Paper 1MathematicsSingle Correct OptionHard

Sequences and Series

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 1 Mathematics Q51] Let the mathematical relation governing Arithmetico-Geometric Progression (AGP) and Infinite Sum Convergence in Sequences and Series be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Sequences and Series)

Q1Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 2 Physics Q1] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 2

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q2Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 2 Physics Q2] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 4

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q3Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 2 Physics Q3] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 6

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q4Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 2 Physics Q4] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 8

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q5Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 2 Physics Q5] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 10

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q6Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 2 Physics Q6] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 12

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q7Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 2 Physics Q7] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 14

. Find the exact response:

Q8Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 2 Physics Q8] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 16

. Find the exact response:

Q9Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 2 Physics Q9] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 18

. Find the exact response:

Q10Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 2 Physics Q10] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 20

. Find the exact response:

Q11Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 2 Physics Q11] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 22

. Find the exact response:

Q12Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 2 Physics Q12] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 24

. Find the exact response:

Q13Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 2 Physics Q13] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 26

. Find the exact response:

Q14Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 2 Physics Q14] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 28

. Find the exact response:

Q15Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 2 Physics Q15] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 30

. Find the exact response:

Q16Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 2 Physics Q16] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 32

. Find the exact response:

Q17Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 2 Physics Q17] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 34

. Find the exact response:

Q18Paper 2Chemistry (Physical)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 2 Chemistry Q18] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q19Paper 2Chemistry (Inorganic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 2 Chemistry Q19] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q20Paper 2Chemistry (Organic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 2 Chemistry Q20] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q21Paper 2Chemistry (Physical)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 2 Chemistry Q21] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q22Paper 2Chemistry (Organic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 2 Chemistry Q22] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q23Paper 2Chemistry (Inorganic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 2 Chemistry Q23] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q24Paper 2Chemistry (Physical)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 2 Chemistry Q24] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q25Paper 2Chemistry (Inorganic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 2 Chemistry Q25] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q26Paper 2Chemistry (Organic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 2 Chemistry Q26] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q27Paper 2Chemistry (Physical)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 2 Chemistry Q27] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q28Paper 2Chemistry (Organic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 2 Chemistry Q28] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q29Paper 2Chemistry (Inorganic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 2 Chemistry Q29] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q30Paper 2Chemistry (Physical)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 2 Chemistry Q30] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q31Paper 2Chemistry (Inorganic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 2 Chemistry Q31] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q32Paper 2Chemistry (Organic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 2 Chemistry Q32] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q33Paper 2Chemistry (Physical)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 2 Chemistry Q33] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q34Paper 2Chemistry (Organic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 2 Chemistry Q34] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q35Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 2 Mathematics Q35] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q36Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 2 Mathematics Q36] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q37Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 2 Mathematics Q37] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q38Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 2 Mathematics Q38] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q39Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 2 Mathematics Q39] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q40Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2024 Paper 2 Mathematics Q40] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q41Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 2 Mathematics Q41] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q42Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 2 Mathematics Q42] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q43Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 2 Mathematics Q43] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q44Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 2 Mathematics Q44] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q45Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 2 Mathematics Q45] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q46Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2024 Paper 2 Mathematics Q46] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q47Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 2 Mathematics Q47] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q48Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 2 Mathematics Q48] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q49Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 2 Mathematics Q49] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q50Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 2 Mathematics Q50] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q51Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2024 Paper 2 Mathematics Q51] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q1Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Rotational Motion & Rigid Body Dynamics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 1 Physics Q1] A thin uniform circular disc of mass

M

and radius

R

is placed on a rough horizontal surface with coefficient of friction

\mu

. At time

t=0

, a horizontal impulse

J

is applied at a height

h = \frac{R}{2}

above the center of mass. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Rotational Motion & Rigid Body Dynamics)

Q2Paper 1PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrostatics & Electric Potential

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 1 Physics Q2] A point charge

+q

is located at a distance

d

from the planar boundary of an infinite semi-infinite dielectric medium with dielectric constant

K > 1

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Electrostatics & Electric Potential)

Q3Paper 1PhysicsSingle Correct OptionHard

Thermodynamics & Kinetic Theory

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 1 Physics Q3] One mole of an ideal gas has a molar heat capacity at constant volume that varies with absolute temperature according to

C_V = C_0 + \alpha T

, where

C_0

and

\alpha

are positive constants. The gas undergoes a quasi-static adiabatic process from initial state

(T_1, V_1)

to final state

(T_2, V_2)

. The relation between

T

and

V

is given by:

Practice JEE Main Level (Thermodynamics & Kinetic Theory)

Q4Paper 1PhysicsNumerical Value TypeTough / Advanced

Electromagnetic Induction & Alternating Current

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 1 Physics Q4] A circular wire loop of radius

a = 0.1\text{ m}

and resistance

R = 2\,\Omega

is placed in a uniform magnetic field

B(t) = B_0 \cos(\omega t)

directed perpendicular to the loop, where

B_0 = 1\text{ T}

and

\omega = 100\text{ rad/s}

. If self-inductance of the loop is

L = 0.02\text{ H}

, find the peak magnitude of current (in Amperes) induced in the loop. (Take

\pi \approx 3.14

, calculate to two decimal places).

Practice JEE Main Level (Electromagnetic Induction & Alternating Current)

Q5Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Wave Optics & Interference

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 1 Physics Q5] In a standard YDSE setup with slit separation

d

and screen distance

D

, a transparent thin film of thickness

t

is placed in front of one slit. The refractive index of the film varies along its thickness

y

as

\mu(y) = \mu_0 + \beta y

for

0 \le y \le t

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Wave Optics & Interference)

Q6Paper 1PhysicsSingle Correct OptionHard

Modern Physics & Quantum Mechanics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 1 Physics Q6] A hydrogen-like atom consists of a nucleus of mass

M

and charge

+Z e

and an electron of mass

m_e

and charge

-e

. Taking finite nuclear mass into account via reduced mass

\mu = \frac{m_e M}{m_e + M}

, the Rydberg constant

R_M

for this atom is related to the infinite nuclear mass Rydberg constant

R_\infty

by:

Practice JEE Main Level (Modern Physics & Quantum Mechanics)

Q7Paper 1PhysicsNumerical Value TypeTough / Advanced

Fluid Mechanics & Surface Tension

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 1 Physics Q7] A clean glass capillary tube of internal radius

r = 0.5\text{ mm}

is dipped vertically into water of surface tension

T = 0.075\text{ N/m}

, contact angle

\theta = 0^\circ

, and density

\rho = 1000\text{ kg/m}^3

. What is the equilibrium height

h

(in mm) of the water column in the capillary tube? (Take

g = 10\text{ m/s}^2

).

Practice JEE Main Level (Fluid Mechanics & Surface Tension)

Q8Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Mechanics & Gravitation

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 1 Physics Q8] A physical system operating under Mechanics & Gravitation is analyzed for Kepler Orbit & Angular Momentum in Elliptical Trajectory. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Mechanics & Gravitation)

Q9Paper 1PhysicsOne or More Correct (Partial Marking)Medium

Oscillations & SHM

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 1 Physics Q9] A physical system operating under Oscillations & SHM is analyzed for Coupled Spring Mass System & Normal Modes. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Oscillations & SHM)

Q10Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Magnetic Effects of Current

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 1 Physics Q10] A physical system operating under Magnetic Effects of Current is analyzed for Cyclotron Motion in Crossed Electric and Magnetic Fields. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Magnetic Effects of Current)

Q11Paper 1PhysicsNumerical Value TypeMedium

Ray Optics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 1 Physics Q11] A physical system operating under Ray Optics is analyzed for Refraction through Silvered Prism & Dispersion without Deviation. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Ray Optics)

Q12Paper 1PhysicsNumerical Value TypeHard

Alternating Current

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 1 Physics Q12] A physical system operating under Alternating Current is analyzed for LCR Resonance & Quality Factor Sharpness. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Alternating Current)

Q13Paper 1PhysicsNumerical Value TypeMedium

Semiconductors

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 1 Physics Q13] A physical system operating under Semiconductors is analyzed for Zener Diode Voltage Regulator with Variable Load. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Semiconductors)

Q14Paper 1PhysicsNumerical Value TypeHard

Nuclear Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 1 Physics Q14] A physical system operating under Nuclear Physics is analyzed for Successive Radioactive Decay & Secular Equilibrium. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Nuclear Physics)

Q15Paper 1PhysicsSingle Correct OptionMedium

Wave Motion

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 1 Physics Q15] A physical system operating under Wave Motion is analyzed for Doppler Effect with Reflected Echo from Moving Reflector. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Wave Motion)

Q16Paper 1PhysicsSingle Correct OptionHard

Work Energy Power

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 1 Physics Q16] A physical system operating under Work Energy Power is analyzed for Vertical Circular Motion with Critical Tension at Zenith. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Work Energy Power)

Q17Paper 1PhysicsSingle Correct OptionMedium

Kinematics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 1 Physics Q17] A physical system operating under Kinematics is analyzed for Relative Motion in 2D River Swimmer Shortest Time vs Shortest Path. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Kinematics)

Q18Paper 1Chemistry (Physical)Single Correct OptionMedium

Coordination Compounds & Qualitative Inorganic Analysis

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 1 Chemistry Q18] Among the following octahedral coordination complexes, which one exhibits the highest crystal field stabilization energy (CFSE) in terms of magnitude of

\Delta_o

and possesses zero unpaired electrons (

n=0

)?

Practice JEE Main Level (Coordination Compounds & Qualitative Inorganic Analysis)

Q19Paper 1Chemistry (Inorganic)One or More Correct (Partial Marking)Hard

Organic Chemistry & Reaction Mechanisms

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 1 Chemistry Q19] Treatment of 2,3-dimethylbutane-2,3-diol (Pinacol) with concentrated sulphuric acid (

H_2SO_4

) at elevated temperature yields 3,3-dimethylbutan-2-one (Pinacolone). Which of the following statements concerning this reaction is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Organic Chemistry & Reaction Mechanisms)

Q20Paper 1Chemistry (Organic)One or More Correct (Partial Marking)Hard

Chemical Kinetics & Radioactivity

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 1 Chemistry Q20] In a detailed investigation of Consecutive First Order Reactions & Steady State Approximation under Chemical Kinetics & Radioactivity, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Chemical Kinetics & Radioactivity)

Q21Paper 1Chemistry (Physical)One or More Correct (Partial Marking)Medium

Thermodynamics & Thermochemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 1 Chemistry Q21] In a detailed investigation of Born-Haber Cycle & Lattice Energy Calculations under Thermodynamics & Thermochemistry, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Thermodynamics & Thermochemistry)

Q22Paper 1Chemistry (Organic)One or More Correct (Partial Marking)Hard

Electrochemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 1 Chemistry Q22] In a detailed investigation of Concentration Cell with Transference & Liquid Junction Potential under Electrochemistry, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Electrochemistry)

Q23Paper 1Chemistry (Inorganic)One or More Correct (Partial Marking)Medium

Chemical & Ionic Equilibrium

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 1 Chemistry Q23] In a detailed investigation of Simultaneous Solubility in Amphoteric Hydroxide Solutions under Chemical & Ionic Equilibrium, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Chemical & Ionic Equilibrium)

Q24Paper 1Chemistry (Physical)One or More Correct (Partial Marking)Hard

Solid State

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 1 Chemistry Q24] In a detailed investigation of Radius Ratio & Octahedral vs Tetrahedral Void Occupancy under Solid State, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Solid State)

Q25Paper 1Chemistry (Inorganic)Numerical Value TypeMedium

Solutions & Colligative Properties

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 1 Chemistry Q25] In a detailed investigation of Van't Hoff Factor in Dimerization and Association Equilibria under Solutions & Colligative Properties, consider the reacting mixture and mechanism:

Practice JEE Main Level (Solutions & Colligative Properties)

Q26Paper 1Chemistry (Organic)Numerical Value TypeHard

p-Block Elements

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 1 Chemistry Q26] In a detailed investigation of Oxyacids of Phosphorus & Silicon Polymers Structure under p-Block Elements, consider the reacting mixture and mechanism:

Practice JEE Main Level (p-Block Elements)

Q27Paper 1Chemistry (Physical)Numerical Value TypeMedium

d- and f-Block Elements

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 1 Chemistry Q27] In a detailed investigation of Lanthanoid Contraction & Separation of Rare Earth Ions under d- and f-Block Elements, consider the reacting mixture and mechanism:

Practice JEE Main Level (d- and f-Block Elements)

Q28Paper 1Chemistry (Organic)Numerical Value TypeHard

Metallurgy & Extraction

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 1 Chemistry Q28] In a detailed investigation of Ellingham Diagram & Thermodynamic Feasibility of Smelting under Metallurgy & Extraction, consider the reacting mixture and mechanism:

Practice JEE Main Level (Metallurgy & Extraction)

Q29Paper 1Chemistry (Inorganic)Numerical Value TypeMedium

Aldehydes, Ketones and Carboxylic Acids

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 1 Chemistry Q29] In a detailed investigation of Intramolecular Aldol & Michael Addition Sequence under Aldehydes, Ketones and Carboxylic Acids, consider the reacting mixture and mechanism:

Practice JEE Main Level (Aldehydes, Ketones and Carboxylic Acids)

Q30Paper 1Chemistry (Physical)Single Correct OptionHard

Aromatic Compounds

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 1 Chemistry Q30] In a detailed investigation of Electrophilic Aromatic Substitution with Directing Groups under Aromatic Compounds, consider the reacting mixture and mechanism:

Practice JEE Main Level (Aromatic Compounds)

Q31Paper 1Chemistry (Inorganic)Single Correct OptionMedium

Amines & Diazonium Salts

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 1 Chemistry Q31] In a detailed investigation of Sandmeyer Reaction vs Gattermann Synthesis Mechanisms under Amines & Diazonium Salts, consider the reacting mixture and mechanism:

Practice JEE Main Level (Amines & Diazonium Salts)

Q32Paper 1Chemistry (Organic)Single Correct OptionHard

Biomolecules & Polymers

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 1 Chemistry Q32] In a detailed investigation of Mutarotation in Glucose & Peptide Linkage Conformation under Biomolecules & Polymers, consider the reacting mixture and mechanism:

Practice JEE Main Level (Biomolecules & Polymers)

Q33Paper 1Chemistry (Physical)Single Correct OptionMedium

Haloalkanes & Haloarenes

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 1 Chemistry Q33] In a detailed investigation of SN1 vs SN2 vs SNi Mechanisms with Stereochemical Inversion under Haloalkanes & Haloarenes, consider the reacting mixture and mechanism:

Practice JEE Main Level (Haloalkanes & Haloarenes)

Q34Paper 1Chemistry (Organic)Single Correct OptionHard

Qualitative Inorganic Salt Analysis

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 1 Chemistry Q34] In a detailed investigation of Chromyl Chloride Test & Brown Ring Complex Formation under Qualitative Inorganic Salt Analysis, consider the reacting mixture and mechanism:

Practice JEE Main Level (Qualitative Inorganic Salt Analysis)

Q35Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Integral Calculus (Definite Integrals & Differential Equations)

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 1 Mathematics Q35] Let

f: (0, \infty) \to \mathbb{R}

be a differentiable function satisfying

f(1) = 1

and

x \int_1^x f(t) dt = (x+1) \int_1^x t f(t) dt

for all

x > 0

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Integral Calculus (Definite Integrals & Differential Equations))

Q36Paper 1MathematicsNumerical Value TypeMedium

Vectors and 3D Geometry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 1 Mathematics Q36] Find the shortest distance between the two skew straight lines

L_1: \vec{r}_1 = (\hat{i} + 2\hat{j} + 3\hat{k}) + \lambda (2\hat{i} + 3\hat{j} + 4\hat{k})

and

L_2: \vec{r}_2 = (2\hat{i} + 4\hat{j} + 5\hat{k}) + \mu (3\hat{i} + 4\hat{j} + 5\hat{k})

. Give the exact distance squared (

d^2

).

Practice JEE Main Level (Vectors and 3D Geometry)

Q37Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Complex Numbers & Quadratic Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 1 Mathematics Q37] Let the mathematical relation governing Geometry of Circles and Apollonius Circles in Complex Plane in Complex Numbers & Quadratic Equations be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Complex Numbers & Quadratic Equations)

Q38Paper 1MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Matrices and Determinants

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 1 Mathematics Q38] Let the mathematical relation governing Cayley-Hamilton Theorem and Inverse of Orthogonal Matrices in Matrices and Determinants be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Matrices and Determinants)

Q39Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Probability & Statistics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 1 Mathematics Q39] Let the mathematical relation governing Bayes Theorem in Multi-Urn Sampling with Replacement in Probability & Statistics be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Probability & Statistics)

Q40Paper 1MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Permutations and Combinations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 1 Mathematics Q40] Let the mathematical relation governing Derangements and Multinomial Distribution Coefficients in Permutations and Combinations be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Permutations and Combinations)

Q41Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Differential Calculus (Continuity & AOD)

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 1 Mathematics Q41] Let the mathematical relation governing Lagrange Mean Value Theorem and Monotonicity Intervals in Differential Calculus (Continuity & AOD) be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Differential Calculus (Continuity & AOD))

Q42Paper 1MathematicsNumerical Value TypeTough / Advanced

Application of Derivatives (Maxima & Minima)

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 1 Mathematics Q42] Let the mathematical relation governing Optimization on Parametric Curves with Constraint Geometry in Application of Derivatives (Maxima & Minima) be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Application of Derivatives (Maxima & Minima))

Q43Paper 1MathematicsNumerical Value TypeHard

Definite Integration

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 1 Mathematics Q43] Let the mathematical relation governing King Rule and Reduction Formula for Trigonometric Powers in Definite Integration be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Definite Integration)

Q44Paper 1MathematicsNumerical Value TypeTough / Advanced

Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 1 Mathematics Q44] Let the mathematical relation governing Bernoulli Differential Equation with Variable Substitution in Differential Equations be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Differential Equations)

Q45Paper 1MathematicsNumerical Value TypeHard

Coordinate Geometry - Parabola

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 1 Mathematics Q45] Let the mathematical relation governing Co-normal Points and Locus of Point of Intersection of Tangents in Coordinate Geometry - Parabola be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Coordinate Geometry - Parabola)

Q46Paper 1MathematicsNumerical Value TypeTough / Advanced

Coordinate Geometry - Ellipse & Hyperbola

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 1 Mathematics Q46] Let the mathematical relation governing Director Circle and Asymptotes of Conjugate Hyperbolas in Coordinate Geometry - Ellipse & Hyperbola be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Coordinate Geometry - Ellipse & Hyperbola)

Q47Paper 1MathematicsSingle Correct OptionHard

Trigonometry & Inverse Trigonometric Functions

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 1 Mathematics Q47] Let the mathematical relation governing Summation of Inverse Trigonometric Series via Telescoping in Trigonometry & Inverse Trigonometric Functions be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Trigonometry & Inverse Trigonometric Functions)

Q48Paper 1MathematicsSingle Correct OptionTough / Advanced

Binomial Theorem

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 1 Mathematics Q48] Let the mathematical relation governing Double Summation and Coefficients of Generalized Multinomial Series in Binomial Theorem be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Binomial Theorem)

Q49Paper 1MathematicsSingle Correct OptionHard

Limits, Continuity and Differentiability

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 1 Mathematics Q49] Let the mathematical relation governing Evaluation of

1^\infty

Indeterminate Form and Squeeze Theorem in Limits, Continuity and Differentiability be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Limits, Continuity and Differentiability)

Q50Paper 1MathematicsSingle Correct OptionTough / Advanced

Functions & Relations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 1 Mathematics Q50] Let the mathematical relation governing Functional Equations and Injective/Surjective Mapping Properties in Functions & Relations be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Functions & Relations)

Q51Paper 1MathematicsSingle Correct OptionHard

Sequences and Series

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 1 Mathematics Q51] Let the mathematical relation governing Arithmetico-Geometric Progression (AGP) and Infinite Sum Convergence in Sequences and Series be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Sequences and Series)

Q1Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 2 Physics Q1] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 2

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q2Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 2 Physics Q2] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 4

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q3Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 2 Physics Q3] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 6

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q4Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 2 Physics Q4] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 8

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q5Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 2 Physics Q5] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 10

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q6Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 2 Physics Q6] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 12

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q7Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 2 Physics Q7] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 14

. Find the exact response:

Q8Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 2 Physics Q8] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 16

. Find the exact response:

Q9Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 2 Physics Q9] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 18

. Find the exact response:

Q10Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 2 Physics Q10] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 20

. Find the exact response:

Q11Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 2 Physics Q11] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 22

. Find the exact response:

Q12Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 2 Physics Q12] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 24

. Find the exact response:

Q13Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 2 Physics Q13] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 26

. Find the exact response:

Q14Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 2 Physics Q14] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 28

. Find the exact response:

Q15Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 2 Physics Q15] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 30

. Find the exact response:

Q16Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 2 Physics Q16] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 32

. Find the exact response:

Q17Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 2 Physics Q17] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 34

. Find the exact response:

Q18Paper 2Chemistry (Physical)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 2 Chemistry Q18] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q19Paper 2Chemistry (Inorganic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 2 Chemistry Q19] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q20Paper 2Chemistry (Organic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 2 Chemistry Q20] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q21Paper 2Chemistry (Physical)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 2 Chemistry Q21] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q22Paper 2Chemistry (Organic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 2 Chemistry Q22] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q23Paper 2Chemistry (Inorganic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 2 Chemistry Q23] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q24Paper 2Chemistry (Physical)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 2 Chemistry Q24] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q25Paper 2Chemistry (Inorganic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 2 Chemistry Q25] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q26Paper 2Chemistry (Organic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 2 Chemistry Q26] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q27Paper 2Chemistry (Physical)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 2 Chemistry Q27] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q28Paper 2Chemistry (Organic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 2 Chemistry Q28] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q29Paper 2Chemistry (Inorganic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 2 Chemistry Q29] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q30Paper 2Chemistry (Physical)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 2 Chemistry Q30] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q31Paper 2Chemistry (Inorganic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 2 Chemistry Q31] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q32Paper 2Chemistry (Organic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 2 Chemistry Q32] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q33Paper 2Chemistry (Physical)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 2 Chemistry Q33] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q34Paper 2Chemistry (Organic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 2 Chemistry Q34] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q35Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 2 Mathematics Q35] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q36Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 2 Mathematics Q36] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q37Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 2 Mathematics Q37] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q38Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 2 Mathematics Q38] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q39Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 2 Mathematics Q39] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q40Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2023 Paper 2 Mathematics Q40] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q41Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 2 Mathematics Q41] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q42Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 2 Mathematics Q42] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q43Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 2 Mathematics Q43] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q44Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 2 Mathematics Q44] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q45Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 2 Mathematics Q45] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q46Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2023 Paper 2 Mathematics Q46] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q47Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 2 Mathematics Q47] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q48Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 2 Mathematics Q48] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q49Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 2 Mathematics Q49] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q50Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 2 Mathematics Q50] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q51Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2023 Paper 2 Mathematics Q51] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q1Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Rotational Motion & Rigid Body Dynamics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 1 Physics Q1] A thin uniform circular disc of mass

M

and radius

R

is placed on a rough horizontal surface with coefficient of friction

\mu

. At time

t=0

, a horizontal impulse

J

is applied at a height

h = \frac{R}{2}

above the center of mass. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Rotational Motion & Rigid Body Dynamics)

Q2Paper 1PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrostatics & Electric Potential

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 1 Physics Q2] A point charge

+q

is located at a distance

d

from the planar boundary of an infinite semi-infinite dielectric medium with dielectric constant

K > 1

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Electrostatics & Electric Potential)

Q3Paper 1PhysicsSingle Correct OptionHard

Thermodynamics & Kinetic Theory

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 1 Physics Q3] One mole of an ideal gas has a molar heat capacity at constant volume that varies with absolute temperature according to

C_V = C_0 + \alpha T

, where

C_0

and

\alpha

are positive constants. The gas undergoes a quasi-static adiabatic process from initial state

(T_1, V_1)

to final state

(T_2, V_2)

. The relation between

T

and

V

is given by:

Practice JEE Main Level (Thermodynamics & Kinetic Theory)

Q4Paper 1PhysicsNumerical Value TypeTough / Advanced

Electromagnetic Induction & Alternating Current

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 1 Physics Q4] A circular wire loop of radius

a = 0.1\text{ m}

and resistance

R = 2\,\Omega

is placed in a uniform magnetic field

B(t) = B_0 \cos(\omega t)

directed perpendicular to the loop, where

B_0 = 1\text{ T}

and

\omega = 100\text{ rad/s}

. If self-inductance of the loop is

L = 0.02\text{ H}

, find the peak magnitude of current (in Amperes) induced in the loop. (Take

\pi \approx 3.14

, calculate to two decimal places).

Practice JEE Main Level (Electromagnetic Induction & Alternating Current)

Q5Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Wave Optics & Interference

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 1 Physics Q5] In a standard YDSE setup with slit separation

d

and screen distance

D

, a transparent thin film of thickness

t

is placed in front of one slit. The refractive index of the film varies along its thickness

y

as

\mu(y) = \mu_0 + \beta y

for

0 \le y \le t

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Wave Optics & Interference)

Q6Paper 1PhysicsSingle Correct OptionHard

Modern Physics & Quantum Mechanics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 1 Physics Q6] A hydrogen-like atom consists of a nucleus of mass

M

and charge

+Z e

and an electron of mass

m_e

and charge

-e

. Taking finite nuclear mass into account via reduced mass

\mu = \frac{m_e M}{m_e + M}

, the Rydberg constant

R_M

for this atom is related to the infinite nuclear mass Rydberg constant

R_\infty

by:

Practice JEE Main Level (Modern Physics & Quantum Mechanics)

Q7Paper 1PhysicsNumerical Value TypeTough / Advanced

Fluid Mechanics & Surface Tension

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 1 Physics Q7] A clean glass capillary tube of internal radius

r = 0.5\text{ mm}

is dipped vertically into water of surface tension

T = 0.075\text{ N/m}

, contact angle

\theta = 0^\circ

, and density

\rho = 1000\text{ kg/m}^3

. What is the equilibrium height

h

(in mm) of the water column in the capillary tube? (Take

g = 10\text{ m/s}^2

).

Practice JEE Main Level (Fluid Mechanics & Surface Tension)

Q8Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Mechanics & Gravitation

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 1 Physics Q8] A physical system operating under Mechanics & Gravitation is analyzed for Kepler Orbit & Angular Momentum in Elliptical Trajectory. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Mechanics & Gravitation)

Q9Paper 1PhysicsOne or More Correct (Partial Marking)Medium

Oscillations & SHM

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 1 Physics Q9] A physical system operating under Oscillations & SHM is analyzed for Coupled Spring Mass System & Normal Modes. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Oscillations & SHM)

Q10Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Magnetic Effects of Current

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 1 Physics Q10] A physical system operating under Magnetic Effects of Current is analyzed for Cyclotron Motion in Crossed Electric and Magnetic Fields. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Magnetic Effects of Current)

Q11Paper 1PhysicsNumerical Value TypeMedium

Ray Optics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 1 Physics Q11] A physical system operating under Ray Optics is analyzed for Refraction through Silvered Prism & Dispersion without Deviation. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Ray Optics)

Q12Paper 1PhysicsNumerical Value TypeHard

Alternating Current

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 1 Physics Q12] A physical system operating under Alternating Current is analyzed for LCR Resonance & Quality Factor Sharpness. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Alternating Current)

Q13Paper 1PhysicsNumerical Value TypeMedium

Semiconductors

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 1 Physics Q13] A physical system operating under Semiconductors is analyzed for Zener Diode Voltage Regulator with Variable Load. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Semiconductors)

Q14Paper 1PhysicsNumerical Value TypeHard

Nuclear Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 1 Physics Q14] A physical system operating under Nuclear Physics is analyzed for Successive Radioactive Decay & Secular Equilibrium. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Nuclear Physics)

Q15Paper 1PhysicsSingle Correct OptionMedium

Wave Motion

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 1 Physics Q15] A physical system operating under Wave Motion is analyzed for Doppler Effect with Reflected Echo from Moving Reflector. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Wave Motion)

Q16Paper 1PhysicsSingle Correct OptionHard

Work Energy Power

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 1 Physics Q16] A physical system operating under Work Energy Power is analyzed for Vertical Circular Motion with Critical Tension at Zenith. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Work Energy Power)

Q17Paper 1PhysicsSingle Correct OptionMedium

Kinematics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 1 Physics Q17] A physical system operating under Kinematics is analyzed for Relative Motion in 2D River Swimmer Shortest Time vs Shortest Path. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Kinematics)

Q18Paper 1Chemistry (Physical)Single Correct OptionMedium

Coordination Compounds & Qualitative Inorganic Analysis

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 1 Chemistry Q18] Among the following octahedral coordination complexes, which one exhibits the highest crystal field stabilization energy (CFSE) in terms of magnitude of

\Delta_o

and possesses zero unpaired electrons (

n=0

)?

Practice JEE Main Level (Coordination Compounds & Qualitative Inorganic Analysis)

Q19Paper 1Chemistry (Inorganic)One or More Correct (Partial Marking)Hard

Organic Chemistry & Reaction Mechanisms

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 1 Chemistry Q19] Treatment of 2,3-dimethylbutane-2,3-diol (Pinacol) with concentrated sulphuric acid (

H_2SO_4

) at elevated temperature yields 3,3-dimethylbutan-2-one (Pinacolone). Which of the following statements concerning this reaction is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Organic Chemistry & Reaction Mechanisms)

Q20Paper 1Chemistry (Organic)One or More Correct (Partial Marking)Hard

Chemical Kinetics & Radioactivity

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 1 Chemistry Q20] In a detailed investigation of Consecutive First Order Reactions & Steady State Approximation under Chemical Kinetics & Radioactivity, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Chemical Kinetics & Radioactivity)

Q21Paper 1Chemistry (Physical)One or More Correct (Partial Marking)Medium

Thermodynamics & Thermochemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 1 Chemistry Q21] In a detailed investigation of Born-Haber Cycle & Lattice Energy Calculations under Thermodynamics & Thermochemistry, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Thermodynamics & Thermochemistry)

Q22Paper 1Chemistry (Organic)One or More Correct (Partial Marking)Hard

Electrochemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 1 Chemistry Q22] In a detailed investigation of Concentration Cell with Transference & Liquid Junction Potential under Electrochemistry, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Electrochemistry)

Q23Paper 1Chemistry (Inorganic)One or More Correct (Partial Marking)Medium

Chemical & Ionic Equilibrium

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 1 Chemistry Q23] In a detailed investigation of Simultaneous Solubility in Amphoteric Hydroxide Solutions under Chemical & Ionic Equilibrium, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Chemical & Ionic Equilibrium)

Q24Paper 1Chemistry (Physical)One or More Correct (Partial Marking)Hard

Solid State

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 1 Chemistry Q24] In a detailed investigation of Radius Ratio & Octahedral vs Tetrahedral Void Occupancy under Solid State, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Solid State)

Q25Paper 1Chemistry (Inorganic)Numerical Value TypeMedium

Solutions & Colligative Properties

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 1 Chemistry Q25] In a detailed investigation of Van't Hoff Factor in Dimerization and Association Equilibria under Solutions & Colligative Properties, consider the reacting mixture and mechanism:

Practice JEE Main Level (Solutions & Colligative Properties)

Q26Paper 1Chemistry (Organic)Numerical Value TypeHard

p-Block Elements

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 1 Chemistry Q26] In a detailed investigation of Oxyacids of Phosphorus & Silicon Polymers Structure under p-Block Elements, consider the reacting mixture and mechanism:

Practice JEE Main Level (p-Block Elements)

Q27Paper 1Chemistry (Physical)Numerical Value TypeMedium

d- and f-Block Elements

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 1 Chemistry Q27] In a detailed investigation of Lanthanoid Contraction & Separation of Rare Earth Ions under d- and f-Block Elements, consider the reacting mixture and mechanism:

Practice JEE Main Level (d- and f-Block Elements)

Q28Paper 1Chemistry (Organic)Numerical Value TypeHard

Metallurgy & Extraction

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 1 Chemistry Q28] In a detailed investigation of Ellingham Diagram & Thermodynamic Feasibility of Smelting under Metallurgy & Extraction, consider the reacting mixture and mechanism:

Practice JEE Main Level (Metallurgy & Extraction)

Q29Paper 1Chemistry (Inorganic)Numerical Value TypeMedium

Aldehydes, Ketones and Carboxylic Acids

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 1 Chemistry Q29] In a detailed investigation of Intramolecular Aldol & Michael Addition Sequence under Aldehydes, Ketones and Carboxylic Acids, consider the reacting mixture and mechanism:

Practice JEE Main Level (Aldehydes, Ketones and Carboxylic Acids)

Q30Paper 1Chemistry (Physical)Single Correct OptionHard

Aromatic Compounds

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 1 Chemistry Q30] In a detailed investigation of Electrophilic Aromatic Substitution with Directing Groups under Aromatic Compounds, consider the reacting mixture and mechanism:

Practice JEE Main Level (Aromatic Compounds)

Q31Paper 1Chemistry (Inorganic)Single Correct OptionMedium

Amines & Diazonium Salts

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 1 Chemistry Q31] In a detailed investigation of Sandmeyer Reaction vs Gattermann Synthesis Mechanisms under Amines & Diazonium Salts, consider the reacting mixture and mechanism:

Practice JEE Main Level (Amines & Diazonium Salts)

Q32Paper 1Chemistry (Organic)Single Correct OptionHard

Biomolecules & Polymers

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 1 Chemistry Q32] In a detailed investigation of Mutarotation in Glucose & Peptide Linkage Conformation under Biomolecules & Polymers, consider the reacting mixture and mechanism:

Practice JEE Main Level (Biomolecules & Polymers)

Q33Paper 1Chemistry (Physical)Single Correct OptionMedium

Haloalkanes & Haloarenes

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 1 Chemistry Q33] In a detailed investigation of SN1 vs SN2 vs SNi Mechanisms with Stereochemical Inversion under Haloalkanes & Haloarenes, consider the reacting mixture and mechanism:

Practice JEE Main Level (Haloalkanes & Haloarenes)

Q34Paper 1Chemistry (Organic)Single Correct OptionHard

Qualitative Inorganic Salt Analysis

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 1 Chemistry Q34] In a detailed investigation of Chromyl Chloride Test & Brown Ring Complex Formation under Qualitative Inorganic Salt Analysis, consider the reacting mixture and mechanism:

Practice JEE Main Level (Qualitative Inorganic Salt Analysis)

Q35Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Integral Calculus (Definite Integrals & Differential Equations)

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 1 Mathematics Q35] Let

f: (0, \infty) \to \mathbb{R}

be a differentiable function satisfying

f(1) = 1

and

x \int_1^x f(t) dt = (x+1) \int_1^x t f(t) dt

for all

x > 0

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Integral Calculus (Definite Integrals & Differential Equations))

Q36Paper 1MathematicsNumerical Value TypeMedium

Vectors and 3D Geometry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 1 Mathematics Q36] Find the shortest distance between the two skew straight lines

L_1: \vec{r}_1 = (\hat{i} + 2\hat{j} + 3\hat{k}) + \lambda (2\hat{i} + 3\hat{j} + 4\hat{k})

and

L_2: \vec{r}_2 = (2\hat{i} + 4\hat{j} + 5\hat{k}) + \mu (3\hat{i} + 4\hat{j} + 5\hat{k})

. Give the exact distance squared (

d^2

).

Practice JEE Main Level (Vectors and 3D Geometry)

Q37Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Complex Numbers & Quadratic Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 1 Mathematics Q37] Let the mathematical relation governing Geometry of Circles and Apollonius Circles in Complex Plane in Complex Numbers & Quadratic Equations be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Complex Numbers & Quadratic Equations)

Q38Paper 1MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Matrices and Determinants

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 1 Mathematics Q38] Let the mathematical relation governing Cayley-Hamilton Theorem and Inverse of Orthogonal Matrices in Matrices and Determinants be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Matrices and Determinants)

Q39Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Probability & Statistics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 1 Mathematics Q39] Let the mathematical relation governing Bayes Theorem in Multi-Urn Sampling with Replacement in Probability & Statistics be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Probability & Statistics)

Q40Paper 1MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Permutations and Combinations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 1 Mathematics Q40] Let the mathematical relation governing Derangements and Multinomial Distribution Coefficients in Permutations and Combinations be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Permutations and Combinations)

Q41Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Differential Calculus (Continuity & AOD)

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 1 Mathematics Q41] Let the mathematical relation governing Lagrange Mean Value Theorem and Monotonicity Intervals in Differential Calculus (Continuity & AOD) be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Differential Calculus (Continuity & AOD))

Q42Paper 1MathematicsNumerical Value TypeTough / Advanced

Application of Derivatives (Maxima & Minima)

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 1 Mathematics Q42] Let the mathematical relation governing Optimization on Parametric Curves with Constraint Geometry in Application of Derivatives (Maxima & Minima) be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Application of Derivatives (Maxima & Minima))

Q43Paper 1MathematicsNumerical Value TypeHard

Definite Integration

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 1 Mathematics Q43] Let the mathematical relation governing King Rule and Reduction Formula for Trigonometric Powers in Definite Integration be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Definite Integration)

Q44Paper 1MathematicsNumerical Value TypeTough / Advanced

Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 1 Mathematics Q44] Let the mathematical relation governing Bernoulli Differential Equation with Variable Substitution in Differential Equations be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Differential Equations)

Q45Paper 1MathematicsNumerical Value TypeHard

Coordinate Geometry - Parabola

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 1 Mathematics Q45] Let the mathematical relation governing Co-normal Points and Locus of Point of Intersection of Tangents in Coordinate Geometry - Parabola be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Coordinate Geometry - Parabola)

Q46Paper 1MathematicsNumerical Value TypeTough / Advanced

Coordinate Geometry - Ellipse & Hyperbola

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 1 Mathematics Q46] Let the mathematical relation governing Director Circle and Asymptotes of Conjugate Hyperbolas in Coordinate Geometry - Ellipse & Hyperbola be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Coordinate Geometry - Ellipse & Hyperbola)

Q47Paper 1MathematicsSingle Correct OptionHard

Trigonometry & Inverse Trigonometric Functions

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 1 Mathematics Q47] Let the mathematical relation governing Summation of Inverse Trigonometric Series via Telescoping in Trigonometry & Inverse Trigonometric Functions be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Trigonometry & Inverse Trigonometric Functions)

Q48Paper 1MathematicsSingle Correct OptionTough / Advanced

Binomial Theorem

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 1 Mathematics Q48] Let the mathematical relation governing Double Summation and Coefficients of Generalized Multinomial Series in Binomial Theorem be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Binomial Theorem)

Q49Paper 1MathematicsSingle Correct OptionHard

Limits, Continuity and Differentiability

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 1 Mathematics Q49] Let the mathematical relation governing Evaluation of

1^\infty

Indeterminate Form and Squeeze Theorem in Limits, Continuity and Differentiability be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Limits, Continuity and Differentiability)

Q50Paper 1MathematicsSingle Correct OptionTough / Advanced

Functions & Relations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 1 Mathematics Q50] Let the mathematical relation governing Functional Equations and Injective/Surjective Mapping Properties in Functions & Relations be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Functions & Relations)

Q51Paper 1MathematicsSingle Correct OptionHard

Sequences and Series

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 1 Mathematics Q51] Let the mathematical relation governing Arithmetico-Geometric Progression (AGP) and Infinite Sum Convergence in Sequences and Series be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Sequences and Series)

Q1Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 2 Physics Q1] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 2

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q2Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 2 Physics Q2] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 4

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q3Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 2 Physics Q3] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 6

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q4Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 2 Physics Q4] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 8

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q5Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 2 Physics Q5] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 10

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q6Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 2 Physics Q6] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 12

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q7Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 2 Physics Q7] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 14

. Find the exact response:

Q8Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 2 Physics Q8] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 16

. Find the exact response:

Q9Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 2 Physics Q9] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 18

. Find the exact response:

Q10Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 2 Physics Q10] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 20

. Find the exact response:

Q11Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 2 Physics Q11] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 22

. Find the exact response:

Q12Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 2 Physics Q12] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 24

. Find the exact response:

Q13Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 2 Physics Q13] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 26

. Find the exact response:

Q14Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 2 Physics Q14] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 28

. Find the exact response:

Q15Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 2 Physics Q15] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 30

. Find the exact response:

Q16Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 2 Physics Q16] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 32

. Find the exact response:

Q17Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 2 Physics Q17] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 34

. Find the exact response:

Q18Paper 2Chemistry (Physical)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 2 Chemistry Q18] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q19Paper 2Chemistry (Inorganic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 2 Chemistry Q19] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q20Paper 2Chemistry (Organic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 2 Chemistry Q20] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q21Paper 2Chemistry (Physical)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 2 Chemistry Q21] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q22Paper 2Chemistry (Organic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 2 Chemistry Q22] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q23Paper 2Chemistry (Inorganic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 2 Chemistry Q23] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q24Paper 2Chemistry (Physical)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 2 Chemistry Q24] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q25Paper 2Chemistry (Inorganic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 2 Chemistry Q25] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q26Paper 2Chemistry (Organic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 2 Chemistry Q26] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q27Paper 2Chemistry (Physical)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 2 Chemistry Q27] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q28Paper 2Chemistry (Organic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 2 Chemistry Q28] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q29Paper 2Chemistry (Inorganic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 2 Chemistry Q29] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q30Paper 2Chemistry (Physical)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 2 Chemistry Q30] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q31Paper 2Chemistry (Inorganic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 2 Chemistry Q31] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q32Paper 2Chemistry (Organic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 2 Chemistry Q32] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q33Paper 2Chemistry (Physical)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 2 Chemistry Q33] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q34Paper 2Chemistry (Organic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 2 Chemistry Q34] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q35Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 2 Mathematics Q35] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q36Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 2 Mathematics Q36] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q37Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 2 Mathematics Q37] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q38Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 2 Mathematics Q38] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q39Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 2 Mathematics Q39] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q40Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2022 Paper 2 Mathematics Q40] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q41Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 2 Mathematics Q41] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q42Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 2 Mathematics Q42] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q43Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 2 Mathematics Q43] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q44Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 2 Mathematics Q44] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q45Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 2 Mathematics Q45] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q46Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2022 Paper 2 Mathematics Q46] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q47Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 2 Mathematics Q47] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q48Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 2 Mathematics Q48] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q49Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 2 Mathematics Q49] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q50Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 2 Mathematics Q50] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q51Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2022 Paper 2 Mathematics Q51] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q1Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Rotational Motion & Rigid Body Dynamics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 1 Physics Q1] A thin uniform circular disc of mass

M

and radius

R

is placed on a rough horizontal surface with coefficient of friction

\mu

. At time

t=0

, a horizontal impulse

J

is applied at a height

h = \frac{R}{2}

above the center of mass. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Rotational Motion & Rigid Body Dynamics)

Q2Paper 1PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrostatics & Electric Potential

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 1 Physics Q2] A point charge

+q

is located at a distance

d

from the planar boundary of an infinite semi-infinite dielectric medium with dielectric constant

K > 1

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Electrostatics & Electric Potential)

Q3Paper 1PhysicsSingle Correct OptionHard

Thermodynamics & Kinetic Theory

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 1 Physics Q3] One mole of an ideal gas has a molar heat capacity at constant volume that varies with absolute temperature according to

C_V = C_0 + \alpha T

, where

C_0

and

\alpha

are positive constants. The gas undergoes a quasi-static adiabatic process from initial state

(T_1, V_1)

to final state

(T_2, V_2)

. The relation between

T

and

V

is given by:

Practice JEE Main Level (Thermodynamics & Kinetic Theory)

Q4Paper 1PhysicsNumerical Value TypeTough / Advanced

Electromagnetic Induction & Alternating Current

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 1 Physics Q4] A circular wire loop of radius

a = 0.1\text{ m}

and resistance

R = 2\,\Omega

is placed in a uniform magnetic field

B(t) = B_0 \cos(\omega t)

directed perpendicular to the loop, where

B_0 = 1\text{ T}

and

\omega = 100\text{ rad/s}

. If self-inductance of the loop is

L = 0.02\text{ H}

, find the peak magnitude of current (in Amperes) induced in the loop. (Take

\pi \approx 3.14

, calculate to two decimal places).

Practice JEE Main Level (Electromagnetic Induction & Alternating Current)

Q5Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Wave Optics & Interference

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 1 Physics Q5] In a standard YDSE setup with slit separation

d

and screen distance

D

, a transparent thin film of thickness

t

is placed in front of one slit. The refractive index of the film varies along its thickness

y

as

\mu(y) = \mu_0 + \beta y

for

0 \le y \le t

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Wave Optics & Interference)

Q6Paper 1PhysicsSingle Correct OptionHard

Modern Physics & Quantum Mechanics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 1 Physics Q6] A hydrogen-like atom consists of a nucleus of mass

M

and charge

+Z e

and an electron of mass

m_e

and charge

-e

. Taking finite nuclear mass into account via reduced mass

\mu = \frac{m_e M}{m_e + M}

, the Rydberg constant

R_M

for this atom is related to the infinite nuclear mass Rydberg constant

R_\infty

by:

Practice JEE Main Level (Modern Physics & Quantum Mechanics)

Q7Paper 1PhysicsNumerical Value TypeTough / Advanced

Fluid Mechanics & Surface Tension

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 1 Physics Q7] A clean glass capillary tube of internal radius

r = 0.5\text{ mm}

is dipped vertically into water of surface tension

T = 0.075\text{ N/m}

, contact angle

\theta = 0^\circ

, and density

\rho = 1000\text{ kg/m}^3

. What is the equilibrium height

h

(in mm) of the water column in the capillary tube? (Take

g = 10\text{ m/s}^2

).

Practice JEE Main Level (Fluid Mechanics & Surface Tension)

Q8Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Mechanics & Gravitation

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 1 Physics Q8] A physical system operating under Mechanics & Gravitation is analyzed for Kepler Orbit & Angular Momentum in Elliptical Trajectory. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Mechanics & Gravitation)

Q9Paper 1PhysicsOne or More Correct (Partial Marking)Medium

Oscillations & SHM

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 1 Physics Q9] A physical system operating under Oscillations & SHM is analyzed for Coupled Spring Mass System & Normal Modes. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Oscillations & SHM)

Q10Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Magnetic Effects of Current

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 1 Physics Q10] A physical system operating under Magnetic Effects of Current is analyzed for Cyclotron Motion in Crossed Electric and Magnetic Fields. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Magnetic Effects of Current)

Q11Paper 1PhysicsNumerical Value TypeMedium

Ray Optics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 1 Physics Q11] A physical system operating under Ray Optics is analyzed for Refraction through Silvered Prism & Dispersion without Deviation. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Ray Optics)

Q12Paper 1PhysicsNumerical Value TypeHard

Alternating Current

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 1 Physics Q12] A physical system operating under Alternating Current is analyzed for LCR Resonance & Quality Factor Sharpness. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Alternating Current)

Q13Paper 1PhysicsNumerical Value TypeMedium

Semiconductors

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 1 Physics Q13] A physical system operating under Semiconductors is analyzed for Zener Diode Voltage Regulator with Variable Load. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Semiconductors)

Q14Paper 1PhysicsNumerical Value TypeHard

Nuclear Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 1 Physics Q14] A physical system operating under Nuclear Physics is analyzed for Successive Radioactive Decay & Secular Equilibrium. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Nuclear Physics)

Q15Paper 1PhysicsSingle Correct OptionMedium

Wave Motion

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 1 Physics Q15] A physical system operating under Wave Motion is analyzed for Doppler Effect with Reflected Echo from Moving Reflector. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Wave Motion)

Q16Paper 1PhysicsSingle Correct OptionHard

Work Energy Power

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 1 Physics Q16] A physical system operating under Work Energy Power is analyzed for Vertical Circular Motion with Critical Tension at Zenith. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Work Energy Power)

Q17Paper 1PhysicsSingle Correct OptionMedium

Kinematics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 1 Physics Q17] A physical system operating under Kinematics is analyzed for Relative Motion in 2D River Swimmer Shortest Time vs Shortest Path. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Kinematics)

Q18Paper 1Chemistry (Physical)Single Correct OptionMedium

Coordination Compounds & Qualitative Inorganic Analysis

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 1 Chemistry Q18] Among the following octahedral coordination complexes, which one exhibits the highest crystal field stabilization energy (CFSE) in terms of magnitude of

\Delta_o

and possesses zero unpaired electrons (

n=0

)?

Practice JEE Main Level (Coordination Compounds & Qualitative Inorganic Analysis)

Q19Paper 1Chemistry (Inorganic)One or More Correct (Partial Marking)Hard

Organic Chemistry & Reaction Mechanisms

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 1 Chemistry Q19] Treatment of 2,3-dimethylbutane-2,3-diol (Pinacol) with concentrated sulphuric acid (

H_2SO_4

) at elevated temperature yields 3,3-dimethylbutan-2-one (Pinacolone). Which of the following statements concerning this reaction is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Organic Chemistry & Reaction Mechanisms)

Q20Paper 1Chemistry (Organic)One or More Correct (Partial Marking)Hard

Chemical Kinetics & Radioactivity

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 1 Chemistry Q20] In a detailed investigation of Consecutive First Order Reactions & Steady State Approximation under Chemical Kinetics & Radioactivity, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Chemical Kinetics & Radioactivity)

Q21Paper 1Chemistry (Physical)One or More Correct (Partial Marking)Medium

Thermodynamics & Thermochemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 1 Chemistry Q21] In a detailed investigation of Born-Haber Cycle & Lattice Energy Calculations under Thermodynamics & Thermochemistry, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Thermodynamics & Thermochemistry)

Q22Paper 1Chemistry (Organic)One or More Correct (Partial Marking)Hard

Electrochemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 1 Chemistry Q22] In a detailed investigation of Concentration Cell with Transference & Liquid Junction Potential under Electrochemistry, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Electrochemistry)

Q23Paper 1Chemistry (Inorganic)One or More Correct (Partial Marking)Medium

Chemical & Ionic Equilibrium

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 1 Chemistry Q23] In a detailed investigation of Simultaneous Solubility in Amphoteric Hydroxide Solutions under Chemical & Ionic Equilibrium, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Chemical & Ionic Equilibrium)

Q24Paper 1Chemistry (Physical)One or More Correct (Partial Marking)Hard

Solid State

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 1 Chemistry Q24] In a detailed investigation of Radius Ratio & Octahedral vs Tetrahedral Void Occupancy under Solid State, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Solid State)

Q25Paper 1Chemistry (Inorganic)Numerical Value TypeMedium

Solutions & Colligative Properties

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 1 Chemistry Q25] In a detailed investigation of Van't Hoff Factor in Dimerization and Association Equilibria under Solutions & Colligative Properties, consider the reacting mixture and mechanism:

Practice JEE Main Level (Solutions & Colligative Properties)

Q26Paper 1Chemistry (Organic)Numerical Value TypeHard

p-Block Elements

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 1 Chemistry Q26] In a detailed investigation of Oxyacids of Phosphorus & Silicon Polymers Structure under p-Block Elements, consider the reacting mixture and mechanism:

Practice JEE Main Level (p-Block Elements)

Q27Paper 1Chemistry (Physical)Numerical Value TypeMedium

d- and f-Block Elements

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 1 Chemistry Q27] In a detailed investigation of Lanthanoid Contraction & Separation of Rare Earth Ions under d- and f-Block Elements, consider the reacting mixture and mechanism:

Practice JEE Main Level (d- and f-Block Elements)

Q28Paper 1Chemistry (Organic)Numerical Value TypeHard

Metallurgy & Extraction

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 1 Chemistry Q28] In a detailed investigation of Ellingham Diagram & Thermodynamic Feasibility of Smelting under Metallurgy & Extraction, consider the reacting mixture and mechanism:

Practice JEE Main Level (Metallurgy & Extraction)

Q29Paper 1Chemistry (Inorganic)Numerical Value TypeMedium

Aldehydes, Ketones and Carboxylic Acids

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 1 Chemistry Q29] In a detailed investigation of Intramolecular Aldol & Michael Addition Sequence under Aldehydes, Ketones and Carboxylic Acids, consider the reacting mixture and mechanism:

Practice JEE Main Level (Aldehydes, Ketones and Carboxylic Acids)

Q30Paper 1Chemistry (Physical)Single Correct OptionHard

Aromatic Compounds

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 1 Chemistry Q30] In a detailed investigation of Electrophilic Aromatic Substitution with Directing Groups under Aromatic Compounds, consider the reacting mixture and mechanism:

Practice JEE Main Level (Aromatic Compounds)

Q31Paper 1Chemistry (Inorganic)Single Correct OptionMedium

Amines & Diazonium Salts

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 1 Chemistry Q31] In a detailed investigation of Sandmeyer Reaction vs Gattermann Synthesis Mechanisms under Amines & Diazonium Salts, consider the reacting mixture and mechanism:

Practice JEE Main Level (Amines & Diazonium Salts)

Q32Paper 1Chemistry (Organic)Single Correct OptionHard

Biomolecules & Polymers

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 1 Chemistry Q32] In a detailed investigation of Mutarotation in Glucose & Peptide Linkage Conformation under Biomolecules & Polymers, consider the reacting mixture and mechanism:

Practice JEE Main Level (Biomolecules & Polymers)

Q33Paper 1Chemistry (Physical)Single Correct OptionMedium

Haloalkanes & Haloarenes

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 1 Chemistry Q33] In a detailed investigation of SN1 vs SN2 vs SNi Mechanisms with Stereochemical Inversion under Haloalkanes & Haloarenes, consider the reacting mixture and mechanism:

Practice JEE Main Level (Haloalkanes & Haloarenes)

Q34Paper 1Chemistry (Organic)Single Correct OptionHard

Qualitative Inorganic Salt Analysis

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 1 Chemistry Q34] In a detailed investigation of Chromyl Chloride Test & Brown Ring Complex Formation under Qualitative Inorganic Salt Analysis, consider the reacting mixture and mechanism:

Practice JEE Main Level (Qualitative Inorganic Salt Analysis)

Q35Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Integral Calculus (Definite Integrals & Differential Equations)

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 1 Mathematics Q35] Let

f: (0, \infty) \to \mathbb{R}

be a differentiable function satisfying

f(1) = 1

and

x \int_1^x f(t) dt = (x+1) \int_1^x t f(t) dt

for all

x > 0

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Integral Calculus (Definite Integrals & Differential Equations))

Q36Paper 1MathematicsNumerical Value TypeMedium

Vectors and 3D Geometry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 1 Mathematics Q36] Find the shortest distance between the two skew straight lines

L_1: \vec{r}_1 = (\hat{i} + 2\hat{j} + 3\hat{k}) + \lambda (2\hat{i} + 3\hat{j} + 4\hat{k})

and

L_2: \vec{r}_2 = (2\hat{i} + 4\hat{j} + 5\hat{k}) + \mu (3\hat{i} + 4\hat{j} + 5\hat{k})

. Give the exact distance squared (

d^2

).

Practice JEE Main Level (Vectors and 3D Geometry)

Q37Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Complex Numbers & Quadratic Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 1 Mathematics Q37] Let the mathematical relation governing Geometry of Circles and Apollonius Circles in Complex Plane in Complex Numbers & Quadratic Equations be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Complex Numbers & Quadratic Equations)

Q38Paper 1MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Matrices and Determinants

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 1 Mathematics Q38] Let the mathematical relation governing Cayley-Hamilton Theorem and Inverse of Orthogonal Matrices in Matrices and Determinants be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Matrices and Determinants)

Q39Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Probability & Statistics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 1 Mathematics Q39] Let the mathematical relation governing Bayes Theorem in Multi-Urn Sampling with Replacement in Probability & Statistics be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Probability & Statistics)

Q40Paper 1MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Permutations and Combinations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 1 Mathematics Q40] Let the mathematical relation governing Derangements and Multinomial Distribution Coefficients in Permutations and Combinations be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Permutations and Combinations)

Q41Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Differential Calculus (Continuity & AOD)

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 1 Mathematics Q41] Let the mathematical relation governing Lagrange Mean Value Theorem and Monotonicity Intervals in Differential Calculus (Continuity & AOD) be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Differential Calculus (Continuity & AOD))

Q42Paper 1MathematicsNumerical Value TypeTough / Advanced

Application of Derivatives (Maxima & Minima)

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 1 Mathematics Q42] Let the mathematical relation governing Optimization on Parametric Curves with Constraint Geometry in Application of Derivatives (Maxima & Minima) be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Application of Derivatives (Maxima & Minima))

Q43Paper 1MathematicsNumerical Value TypeHard

Definite Integration

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 1 Mathematics Q43] Let the mathematical relation governing King Rule and Reduction Formula for Trigonometric Powers in Definite Integration be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Definite Integration)

Q44Paper 1MathematicsNumerical Value TypeTough / Advanced

Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 1 Mathematics Q44] Let the mathematical relation governing Bernoulli Differential Equation with Variable Substitution in Differential Equations be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Differential Equations)

Q45Paper 1MathematicsNumerical Value TypeHard

Coordinate Geometry - Parabola

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 1 Mathematics Q45] Let the mathematical relation governing Co-normal Points and Locus of Point of Intersection of Tangents in Coordinate Geometry - Parabola be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Coordinate Geometry - Parabola)

Q46Paper 1MathematicsNumerical Value TypeTough / Advanced

Coordinate Geometry - Ellipse & Hyperbola

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 1 Mathematics Q46] Let the mathematical relation governing Director Circle and Asymptotes of Conjugate Hyperbolas in Coordinate Geometry - Ellipse & Hyperbola be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Coordinate Geometry - Ellipse & Hyperbola)

Q47Paper 1MathematicsSingle Correct OptionHard

Trigonometry & Inverse Trigonometric Functions

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 1 Mathematics Q47] Let the mathematical relation governing Summation of Inverse Trigonometric Series via Telescoping in Trigonometry & Inverse Trigonometric Functions be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Trigonometry & Inverse Trigonometric Functions)

Q48Paper 1MathematicsSingle Correct OptionTough / Advanced

Binomial Theorem

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 1 Mathematics Q48] Let the mathematical relation governing Double Summation and Coefficients of Generalized Multinomial Series in Binomial Theorem be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Binomial Theorem)

Q49Paper 1MathematicsSingle Correct OptionHard

Limits, Continuity and Differentiability

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 1 Mathematics Q49] Let the mathematical relation governing Evaluation of

1^\infty

Indeterminate Form and Squeeze Theorem in Limits, Continuity and Differentiability be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Limits, Continuity and Differentiability)

Q50Paper 1MathematicsSingle Correct OptionTough / Advanced

Functions & Relations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 1 Mathematics Q50] Let the mathematical relation governing Functional Equations and Injective/Surjective Mapping Properties in Functions & Relations be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Functions & Relations)

Q51Paper 1MathematicsSingle Correct OptionHard

Sequences and Series

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 1 Mathematics Q51] Let the mathematical relation governing Arithmetico-Geometric Progression (AGP) and Infinite Sum Convergence in Sequences and Series be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Sequences and Series)

Q1Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 2 Physics Q1] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 2

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q2Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 2 Physics Q2] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 4

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q3Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 2 Physics Q3] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 6

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q4Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 2 Physics Q4] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 8

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q5Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 2 Physics Q5] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 10

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q6Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 2 Physics Q6] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 12

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q7Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 2 Physics Q7] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 14

. Find the exact response:

Q8Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 2 Physics Q8] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 16

. Find the exact response:

Q9Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 2 Physics Q9] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 18

. Find the exact response:

Q10Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 2 Physics Q10] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 20

. Find the exact response:

Q11Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 2 Physics Q11] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 22

. Find the exact response:

Q12Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 2 Physics Q12] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 24

. Find the exact response:

Q13Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 2 Physics Q13] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 26

. Find the exact response:

Q14Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 2 Physics Q14] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 28

. Find the exact response:

Q15Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 2 Physics Q15] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 30

. Find the exact response:

Q16Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 2 Physics Q16] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 32

. Find the exact response:

Q17Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 2 Physics Q17] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 34

. Find the exact response:

Q18Paper 2Chemistry (Physical)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 2 Chemistry Q18] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q19Paper 2Chemistry (Inorganic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 2 Chemistry Q19] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q20Paper 2Chemistry (Organic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 2 Chemistry Q20] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q21Paper 2Chemistry (Physical)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 2 Chemistry Q21] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q22Paper 2Chemistry (Organic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 2 Chemistry Q22] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q23Paper 2Chemistry (Inorganic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 2 Chemistry Q23] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q24Paper 2Chemistry (Physical)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 2 Chemistry Q24] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q25Paper 2Chemistry (Inorganic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 2 Chemistry Q25] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q26Paper 2Chemistry (Organic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 2 Chemistry Q26] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q27Paper 2Chemistry (Physical)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 2 Chemistry Q27] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q28Paper 2Chemistry (Organic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 2 Chemistry Q28] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q29Paper 2Chemistry (Inorganic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 2 Chemistry Q29] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q30Paper 2Chemistry (Physical)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 2 Chemistry Q30] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q31Paper 2Chemistry (Inorganic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 2 Chemistry Q31] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q32Paper 2Chemistry (Organic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 2 Chemistry Q32] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q33Paper 2Chemistry (Physical)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 2 Chemistry Q33] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q34Paper 2Chemistry (Organic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 2 Chemistry Q34] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q35Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 2 Mathematics Q35] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q36Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 2 Mathematics Q36] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q37Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 2 Mathematics Q37] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q38Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 2 Mathematics Q38] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q39Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 2 Mathematics Q39] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q40Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2021 Paper 2 Mathematics Q40] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q41Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 2 Mathematics Q41] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q42Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 2 Mathematics Q42] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q43Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 2 Mathematics Q43] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q44Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 2 Mathematics Q44] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q45Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 2 Mathematics Q45] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q46Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2021 Paper 2 Mathematics Q46] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q47Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 2 Mathematics Q47] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q48Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 2 Mathematics Q48] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q49Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 2 Mathematics Q49] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q50Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 2 Mathematics Q50] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q51Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2021 Paper 2 Mathematics Q51] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q1Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Rotational Motion & Rigid Body Dynamics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 1 Physics Q1] A thin uniform circular disc of mass

M

and radius

R

is placed on a rough horizontal surface with coefficient of friction

\mu

. At time

t=0

, a horizontal impulse

J

is applied at a height

h = \frac{R}{2}

above the center of mass. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Rotational Motion & Rigid Body Dynamics)

Q2Paper 1PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrostatics & Electric Potential

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 1 Physics Q2] A point charge

+q

is located at a distance

d

from the planar boundary of an infinite semi-infinite dielectric medium with dielectric constant

K > 1

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Electrostatics & Electric Potential)

Q3Paper 1PhysicsSingle Correct OptionHard

Thermodynamics & Kinetic Theory

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 1 Physics Q3] One mole of an ideal gas has a molar heat capacity at constant volume that varies with absolute temperature according to

C_V = C_0 + \alpha T

, where

C_0

and

\alpha

are positive constants. The gas undergoes a quasi-static adiabatic process from initial state

(T_1, V_1)

to final state

(T_2, V_2)

. The relation between

T

and

V

is given by:

Practice JEE Main Level (Thermodynamics & Kinetic Theory)

Q4Paper 1PhysicsNumerical Value TypeTough / Advanced

Electromagnetic Induction & Alternating Current

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 1 Physics Q4] A circular wire loop of radius

a = 0.1\text{ m}

and resistance

R = 2\,\Omega

is placed in a uniform magnetic field

B(t) = B_0 \cos(\omega t)

directed perpendicular to the loop, where

B_0 = 1\text{ T}

and

\omega = 100\text{ rad/s}

. If self-inductance of the loop is

L = 0.02\text{ H}

, find the peak magnitude of current (in Amperes) induced in the loop. (Take

\pi \approx 3.14

, calculate to two decimal places).

Practice JEE Main Level (Electromagnetic Induction & Alternating Current)

Q5Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Wave Optics & Interference

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 1 Physics Q5] In a standard YDSE setup with slit separation

d

and screen distance

D

, a transparent thin film of thickness

t

is placed in front of one slit. The refractive index of the film varies along its thickness

y

as

\mu(y) = \mu_0 + \beta y

for

0 \le y \le t

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Wave Optics & Interference)

Q6Paper 1PhysicsSingle Correct OptionHard

Modern Physics & Quantum Mechanics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 1 Physics Q6] A hydrogen-like atom consists of a nucleus of mass

M

and charge

+Z e

and an electron of mass

m_e

and charge

-e

. Taking finite nuclear mass into account via reduced mass

\mu = \frac{m_e M}{m_e + M}

, the Rydberg constant

R_M

for this atom is related to the infinite nuclear mass Rydberg constant

R_\infty

by:

Practice JEE Main Level (Modern Physics & Quantum Mechanics)

Q7Paper 1PhysicsNumerical Value TypeTough / Advanced

Fluid Mechanics & Surface Tension

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 1 Physics Q7] A clean glass capillary tube of internal radius

r = 0.5\text{ mm}

is dipped vertically into water of surface tension

T = 0.075\text{ N/m}

, contact angle

\theta = 0^\circ

, and density

\rho = 1000\text{ kg/m}^3

. What is the equilibrium height

h

(in mm) of the water column in the capillary tube? (Take

g = 10\text{ m/s}^2

).

Practice JEE Main Level (Fluid Mechanics & Surface Tension)

Q8Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Mechanics & Gravitation

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 1 Physics Q8] A physical system operating under Mechanics & Gravitation is analyzed for Kepler Orbit & Angular Momentum in Elliptical Trajectory. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Mechanics & Gravitation)

Q9Paper 1PhysicsOne or More Correct (Partial Marking)Medium

Oscillations & SHM

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 1 Physics Q9] A physical system operating under Oscillations & SHM is analyzed for Coupled Spring Mass System & Normal Modes. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Oscillations & SHM)

Q10Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Magnetic Effects of Current

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 1 Physics Q10] A physical system operating under Magnetic Effects of Current is analyzed for Cyclotron Motion in Crossed Electric and Magnetic Fields. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Magnetic Effects of Current)

Q11Paper 1PhysicsNumerical Value TypeMedium

Ray Optics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 1 Physics Q11] A physical system operating under Ray Optics is analyzed for Refraction through Silvered Prism & Dispersion without Deviation. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Ray Optics)

Q12Paper 1PhysicsNumerical Value TypeHard

Alternating Current

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 1 Physics Q12] A physical system operating under Alternating Current is analyzed for LCR Resonance & Quality Factor Sharpness. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Alternating Current)

Q13Paper 1PhysicsNumerical Value TypeMedium

Semiconductors

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 1 Physics Q13] A physical system operating under Semiconductors is analyzed for Zener Diode Voltage Regulator with Variable Load. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Semiconductors)

Q14Paper 1PhysicsNumerical Value TypeHard

Nuclear Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 1 Physics Q14] A physical system operating under Nuclear Physics is analyzed for Successive Radioactive Decay & Secular Equilibrium. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Nuclear Physics)

Q15Paper 1PhysicsSingle Correct OptionMedium

Wave Motion

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 1 Physics Q15] A physical system operating under Wave Motion is analyzed for Doppler Effect with Reflected Echo from Moving Reflector. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Wave Motion)

Q16Paper 1PhysicsSingle Correct OptionHard

Work Energy Power

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 1 Physics Q16] A physical system operating under Work Energy Power is analyzed for Vertical Circular Motion with Critical Tension at Zenith. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Work Energy Power)

Q17Paper 1PhysicsSingle Correct OptionMedium

Kinematics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 1 Physics Q17] A physical system operating under Kinematics is analyzed for Relative Motion in 2D River Swimmer Shortest Time vs Shortest Path. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Kinematics)

Q18Paper 1Chemistry (Physical)Single Correct OptionMedium

Coordination Compounds & Qualitative Inorganic Analysis

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 1 Chemistry Q18] Among the following octahedral coordination complexes, which one exhibits the highest crystal field stabilization energy (CFSE) in terms of magnitude of

\Delta_o

and possesses zero unpaired electrons (

n=0

)?

Practice JEE Main Level (Coordination Compounds & Qualitative Inorganic Analysis)

Q19Paper 1Chemistry (Inorganic)One or More Correct (Partial Marking)Hard

Organic Chemistry & Reaction Mechanisms

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 1 Chemistry Q19] Treatment of 2,3-dimethylbutane-2,3-diol (Pinacol) with concentrated sulphuric acid (

H_2SO_4

) at elevated temperature yields 3,3-dimethylbutan-2-one (Pinacolone). Which of the following statements concerning this reaction is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Organic Chemistry & Reaction Mechanisms)

Q20Paper 1Chemistry (Organic)One or More Correct (Partial Marking)Hard

Chemical Kinetics & Radioactivity

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 1 Chemistry Q20] In a detailed investigation of Consecutive First Order Reactions & Steady State Approximation under Chemical Kinetics & Radioactivity, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Chemical Kinetics & Radioactivity)

Q21Paper 1Chemistry (Physical)One or More Correct (Partial Marking)Medium

Thermodynamics & Thermochemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 1 Chemistry Q21] In a detailed investigation of Born-Haber Cycle & Lattice Energy Calculations under Thermodynamics & Thermochemistry, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Thermodynamics & Thermochemistry)

Q22Paper 1Chemistry (Organic)One or More Correct (Partial Marking)Hard

Electrochemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 1 Chemistry Q22] In a detailed investigation of Concentration Cell with Transference & Liquid Junction Potential under Electrochemistry, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Electrochemistry)

Q23Paper 1Chemistry (Inorganic)One or More Correct (Partial Marking)Medium

Chemical & Ionic Equilibrium

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 1 Chemistry Q23] In a detailed investigation of Simultaneous Solubility in Amphoteric Hydroxide Solutions under Chemical & Ionic Equilibrium, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Chemical & Ionic Equilibrium)

Q24Paper 1Chemistry (Physical)One or More Correct (Partial Marking)Hard

Solid State

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 1 Chemistry Q24] In a detailed investigation of Radius Ratio & Octahedral vs Tetrahedral Void Occupancy under Solid State, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Solid State)

Q25Paper 1Chemistry (Inorganic)Numerical Value TypeMedium

Solutions & Colligative Properties

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 1 Chemistry Q25] In a detailed investigation of Van't Hoff Factor in Dimerization and Association Equilibria under Solutions & Colligative Properties, consider the reacting mixture and mechanism:

Practice JEE Main Level (Solutions & Colligative Properties)

Q26Paper 1Chemistry (Organic)Numerical Value TypeHard

p-Block Elements

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 1 Chemistry Q26] In a detailed investigation of Oxyacids of Phosphorus & Silicon Polymers Structure under p-Block Elements, consider the reacting mixture and mechanism:

Practice JEE Main Level (p-Block Elements)

Q27Paper 1Chemistry (Physical)Numerical Value TypeMedium

d- and f-Block Elements

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 1 Chemistry Q27] In a detailed investigation of Lanthanoid Contraction & Separation of Rare Earth Ions under d- and f-Block Elements, consider the reacting mixture and mechanism:

Practice JEE Main Level (d- and f-Block Elements)

Q28Paper 1Chemistry (Organic)Numerical Value TypeHard

Metallurgy & Extraction

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 1 Chemistry Q28] In a detailed investigation of Ellingham Diagram & Thermodynamic Feasibility of Smelting under Metallurgy & Extraction, consider the reacting mixture and mechanism:

Practice JEE Main Level (Metallurgy & Extraction)

Q29Paper 1Chemistry (Inorganic)Numerical Value TypeMedium

Aldehydes, Ketones and Carboxylic Acids

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 1 Chemistry Q29] In a detailed investigation of Intramolecular Aldol & Michael Addition Sequence under Aldehydes, Ketones and Carboxylic Acids, consider the reacting mixture and mechanism:

Practice JEE Main Level (Aldehydes, Ketones and Carboxylic Acids)

Q30Paper 1Chemistry (Physical)Single Correct OptionHard

Aromatic Compounds

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 1 Chemistry Q30] In a detailed investigation of Electrophilic Aromatic Substitution with Directing Groups under Aromatic Compounds, consider the reacting mixture and mechanism:

Practice JEE Main Level (Aromatic Compounds)

Q31Paper 1Chemistry (Inorganic)Single Correct OptionMedium

Amines & Diazonium Salts

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 1 Chemistry Q31] In a detailed investigation of Sandmeyer Reaction vs Gattermann Synthesis Mechanisms under Amines & Diazonium Salts, consider the reacting mixture and mechanism:

Practice JEE Main Level (Amines & Diazonium Salts)

Q32Paper 1Chemistry (Organic)Single Correct OptionHard

Biomolecules & Polymers

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 1 Chemistry Q32] In a detailed investigation of Mutarotation in Glucose & Peptide Linkage Conformation under Biomolecules & Polymers, consider the reacting mixture and mechanism:

Practice JEE Main Level (Biomolecules & Polymers)

Q33Paper 1Chemistry (Physical)Single Correct OptionMedium

Haloalkanes & Haloarenes

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 1 Chemistry Q33] In a detailed investigation of SN1 vs SN2 vs SNi Mechanisms with Stereochemical Inversion under Haloalkanes & Haloarenes, consider the reacting mixture and mechanism:

Practice JEE Main Level (Haloalkanes & Haloarenes)

Q34Paper 1Chemistry (Organic)Single Correct OptionHard

Qualitative Inorganic Salt Analysis

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 1 Chemistry Q34] In a detailed investigation of Chromyl Chloride Test & Brown Ring Complex Formation under Qualitative Inorganic Salt Analysis, consider the reacting mixture and mechanism:

Practice JEE Main Level (Qualitative Inorganic Salt Analysis)

Q35Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Integral Calculus (Definite Integrals & Differential Equations)

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 1 Mathematics Q35] Let

f: (0, \infty) \to \mathbb{R}

be a differentiable function satisfying

f(1) = 1

and

x \int_1^x f(t) dt = (x+1) \int_1^x t f(t) dt

for all

x > 0

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Integral Calculus (Definite Integrals & Differential Equations))

Q36Paper 1MathematicsNumerical Value TypeMedium

Vectors and 3D Geometry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 1 Mathematics Q36] Find the shortest distance between the two skew straight lines

L_1: \vec{r}_1 = (\hat{i} + 2\hat{j} + 3\hat{k}) + \lambda (2\hat{i} + 3\hat{j} + 4\hat{k})

and

L_2: \vec{r}_2 = (2\hat{i} + 4\hat{j} + 5\hat{k}) + \mu (3\hat{i} + 4\hat{j} + 5\hat{k})

. Give the exact distance squared (

d^2

).

Practice JEE Main Level (Vectors and 3D Geometry)

Q37Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Complex Numbers & Quadratic Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 1 Mathematics Q37] Let the mathematical relation governing Geometry of Circles and Apollonius Circles in Complex Plane in Complex Numbers & Quadratic Equations be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Complex Numbers & Quadratic Equations)

Q38Paper 1MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Matrices and Determinants

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 1 Mathematics Q38] Let the mathematical relation governing Cayley-Hamilton Theorem and Inverse of Orthogonal Matrices in Matrices and Determinants be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Matrices and Determinants)

Q39Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Probability & Statistics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 1 Mathematics Q39] Let the mathematical relation governing Bayes Theorem in Multi-Urn Sampling with Replacement in Probability & Statistics be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Probability & Statistics)

Q40Paper 1MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Permutations and Combinations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 1 Mathematics Q40] Let the mathematical relation governing Derangements and Multinomial Distribution Coefficients in Permutations and Combinations be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Permutations and Combinations)

Q41Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Differential Calculus (Continuity & AOD)

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 1 Mathematics Q41] Let the mathematical relation governing Lagrange Mean Value Theorem and Monotonicity Intervals in Differential Calculus (Continuity & AOD) be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Differential Calculus (Continuity & AOD))

Q42Paper 1MathematicsNumerical Value TypeTough / Advanced

Application of Derivatives (Maxima & Minima)

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 1 Mathematics Q42] Let the mathematical relation governing Optimization on Parametric Curves with Constraint Geometry in Application of Derivatives (Maxima & Minima) be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Application of Derivatives (Maxima & Minima))

Q43Paper 1MathematicsNumerical Value TypeHard

Definite Integration

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 1 Mathematics Q43] Let the mathematical relation governing King Rule and Reduction Formula for Trigonometric Powers in Definite Integration be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Definite Integration)

Q44Paper 1MathematicsNumerical Value TypeTough / Advanced

Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 1 Mathematics Q44] Let the mathematical relation governing Bernoulli Differential Equation with Variable Substitution in Differential Equations be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Differential Equations)

Q45Paper 1MathematicsNumerical Value TypeHard

Coordinate Geometry - Parabola

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 1 Mathematics Q45] Let the mathematical relation governing Co-normal Points and Locus of Point of Intersection of Tangents in Coordinate Geometry - Parabola be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Coordinate Geometry - Parabola)

Q46Paper 1MathematicsNumerical Value TypeTough / Advanced

Coordinate Geometry - Ellipse & Hyperbola

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 1 Mathematics Q46] Let the mathematical relation governing Director Circle and Asymptotes of Conjugate Hyperbolas in Coordinate Geometry - Ellipse & Hyperbola be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Coordinate Geometry - Ellipse & Hyperbola)

Q47Paper 1MathematicsSingle Correct OptionHard

Trigonometry & Inverse Trigonometric Functions

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 1 Mathematics Q47] Let the mathematical relation governing Summation of Inverse Trigonometric Series via Telescoping in Trigonometry & Inverse Trigonometric Functions be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Trigonometry & Inverse Trigonometric Functions)

Q48Paper 1MathematicsSingle Correct OptionTough / Advanced

Binomial Theorem

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 1 Mathematics Q48] Let the mathematical relation governing Double Summation and Coefficients of Generalized Multinomial Series in Binomial Theorem be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Binomial Theorem)

Q49Paper 1MathematicsSingle Correct OptionHard

Limits, Continuity and Differentiability

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 1 Mathematics Q49] Let the mathematical relation governing Evaluation of

1^\infty

Indeterminate Form and Squeeze Theorem in Limits, Continuity and Differentiability be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Limits, Continuity and Differentiability)

Q50Paper 1MathematicsSingle Correct OptionTough / Advanced

Functions & Relations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 1 Mathematics Q50] Let the mathematical relation governing Functional Equations and Injective/Surjective Mapping Properties in Functions & Relations be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Functions & Relations)

Q51Paper 1MathematicsSingle Correct OptionHard

Sequences and Series

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 1 Mathematics Q51] Let the mathematical relation governing Arithmetico-Geometric Progression (AGP) and Infinite Sum Convergence in Sequences and Series be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Sequences and Series)

Q1Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 2 Physics Q1] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 2

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q2Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 2 Physics Q2] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 4

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q3Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 2 Physics Q3] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 6

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q4Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 2 Physics Q4] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 8

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q5Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 2 Physics Q5] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 10

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q6Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 2 Physics Q6] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 12

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q7Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 2 Physics Q7] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 14

. Find the exact response:

Q8Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 2 Physics Q8] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 16

. Find the exact response:

Q9Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 2 Physics Q9] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 18

. Find the exact response:

Q10Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 2 Physics Q10] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 20

. Find the exact response:

Q11Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 2 Physics Q11] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 22

. Find the exact response:

Q12Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 2 Physics Q12] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 24

. Find the exact response:

Q13Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 2 Physics Q13] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 26

. Find the exact response:

Q14Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 2 Physics Q14] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 28

. Find the exact response:

Q15Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 2 Physics Q15] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 30

. Find the exact response:

Q16Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 2 Physics Q16] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 32

. Find the exact response:

Q17Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 2 Physics Q17] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 34

. Find the exact response:

Q18Paper 2Chemistry (Physical)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 2 Chemistry Q18] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q19Paper 2Chemistry (Inorganic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 2 Chemistry Q19] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q20Paper 2Chemistry (Organic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 2 Chemistry Q20] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q21Paper 2Chemistry (Physical)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 2 Chemistry Q21] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q22Paper 2Chemistry (Organic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 2 Chemistry Q22] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q23Paper 2Chemistry (Inorganic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 2 Chemistry Q23] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q24Paper 2Chemistry (Physical)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 2 Chemistry Q24] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q25Paper 2Chemistry (Inorganic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 2 Chemistry Q25] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q26Paper 2Chemistry (Organic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 2 Chemistry Q26] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q27Paper 2Chemistry (Physical)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 2 Chemistry Q27] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q28Paper 2Chemistry (Organic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 2 Chemistry Q28] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q29Paper 2Chemistry (Inorganic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 2 Chemistry Q29] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q30Paper 2Chemistry (Physical)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 2 Chemistry Q30] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q31Paper 2Chemistry (Inorganic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 2 Chemistry Q31] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q32Paper 2Chemistry (Organic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 2 Chemistry Q32] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q33Paper 2Chemistry (Physical)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 2 Chemistry Q33] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q34Paper 2Chemistry (Organic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 2 Chemistry Q34] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q35Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 2 Mathematics Q35] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q36Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 2 Mathematics Q36] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q37Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 2 Mathematics Q37] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q38Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 2 Mathematics Q38] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q39Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 2 Mathematics Q39] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q40Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2020 Paper 2 Mathematics Q40] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q41Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 2 Mathematics Q41] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q42Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 2 Mathematics Q42] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q43Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 2 Mathematics Q43] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q44Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 2 Mathematics Q44] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q45Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 2 Mathematics Q45] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q46Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2020 Paper 2 Mathematics Q46] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q47Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 2 Mathematics Q47] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q48Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 2 Mathematics Q48] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q49Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 2 Mathematics Q49] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q50Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 2 Mathematics Q50] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q51Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2020 Paper 2 Mathematics Q51] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q1Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Rotational Motion & Rigid Body Dynamics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 1 Physics Q1] A thin uniform circular disc of mass

M

and radius

R

is placed on a rough horizontal surface with coefficient of friction

\mu

. At time

t=0

, a horizontal impulse

J

is applied at a height

h = \frac{R}{2}

above the center of mass. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Rotational Motion & Rigid Body Dynamics)

Q2Paper 1PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrostatics & Electric Potential

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 1 Physics Q2] A point charge

+q

is located at a distance

d

from the planar boundary of an infinite semi-infinite dielectric medium with dielectric constant

K > 1

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Electrostatics & Electric Potential)

Q3Paper 1PhysicsSingle Correct OptionHard

Thermodynamics & Kinetic Theory

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 1 Physics Q3] One mole of an ideal gas has a molar heat capacity at constant volume that varies with absolute temperature according to

C_V = C_0 + \alpha T

, where

C_0

and

\alpha

are positive constants. The gas undergoes a quasi-static adiabatic process from initial state

(T_1, V_1)

to final state

(T_2, V_2)

. The relation between

T

and

V

is given by:

Practice JEE Main Level (Thermodynamics & Kinetic Theory)

Q4Paper 1PhysicsNumerical Value TypeTough / Advanced

Electromagnetic Induction & Alternating Current

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 1 Physics Q4] A circular wire loop of radius

a = 0.1\text{ m}

and resistance

R = 2\,\Omega

is placed in a uniform magnetic field

B(t) = B_0 \cos(\omega t)

directed perpendicular to the loop, where

B_0 = 1\text{ T}

and

\omega = 100\text{ rad/s}

. If self-inductance of the loop is

L = 0.02\text{ H}

, find the peak magnitude of current (in Amperes) induced in the loop. (Take

\pi \approx 3.14

, calculate to two decimal places).

Practice JEE Main Level (Electromagnetic Induction & Alternating Current)

Q5Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Wave Optics & Interference

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 1 Physics Q5] In a standard YDSE setup with slit separation

d

and screen distance

D

, a transparent thin film of thickness

t

is placed in front of one slit. The refractive index of the film varies along its thickness

y

as

\mu(y) = \mu_0 + \beta y

for

0 \le y \le t

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Wave Optics & Interference)

Q6Paper 1PhysicsSingle Correct OptionHard

Modern Physics & Quantum Mechanics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 1 Physics Q6] A hydrogen-like atom consists of a nucleus of mass

M

and charge

+Z e

and an electron of mass

m_e

and charge

-e

. Taking finite nuclear mass into account via reduced mass

\mu = \frac{m_e M}{m_e + M}

, the Rydberg constant

R_M

for this atom is related to the infinite nuclear mass Rydberg constant

R_\infty

by:

Practice JEE Main Level (Modern Physics & Quantum Mechanics)

Q7Paper 1PhysicsNumerical Value TypeTough / Advanced

Fluid Mechanics & Surface Tension

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 1 Physics Q7] A clean glass capillary tube of internal radius

r = 0.5\text{ mm}

is dipped vertically into water of surface tension

T = 0.075\text{ N/m}

, contact angle

\theta = 0^\circ

, and density

\rho = 1000\text{ kg/m}^3

. What is the equilibrium height

h

(in mm) of the water column in the capillary tube? (Take

g = 10\text{ m/s}^2

).

Practice JEE Main Level (Fluid Mechanics & Surface Tension)

Q8Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Mechanics & Gravitation

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 1 Physics Q8] A physical system operating under Mechanics & Gravitation is analyzed for Kepler Orbit & Angular Momentum in Elliptical Trajectory. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Mechanics & Gravitation)

Q9Paper 1PhysicsOne or More Correct (Partial Marking)Medium

Oscillations & SHM

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 1 Physics Q9] A physical system operating under Oscillations & SHM is analyzed for Coupled Spring Mass System & Normal Modes. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Oscillations & SHM)

Q10Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Magnetic Effects of Current

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 1 Physics Q10] A physical system operating under Magnetic Effects of Current is analyzed for Cyclotron Motion in Crossed Electric and Magnetic Fields. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Magnetic Effects of Current)

Q11Paper 1PhysicsNumerical Value TypeMedium

Ray Optics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 1 Physics Q11] A physical system operating under Ray Optics is analyzed for Refraction through Silvered Prism & Dispersion without Deviation. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Ray Optics)

Q12Paper 1PhysicsNumerical Value TypeHard

Alternating Current

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 1 Physics Q12] A physical system operating under Alternating Current is analyzed for LCR Resonance & Quality Factor Sharpness. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Alternating Current)

Q13Paper 1PhysicsNumerical Value TypeMedium

Semiconductors

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 1 Physics Q13] A physical system operating under Semiconductors is analyzed for Zener Diode Voltage Regulator with Variable Load. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Semiconductors)

Q14Paper 1PhysicsNumerical Value TypeHard

Nuclear Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 1 Physics Q14] A physical system operating under Nuclear Physics is analyzed for Successive Radioactive Decay & Secular Equilibrium. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Nuclear Physics)

Q15Paper 1PhysicsSingle Correct OptionMedium

Wave Motion

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 1 Physics Q15] A physical system operating under Wave Motion is analyzed for Doppler Effect with Reflected Echo from Moving Reflector. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Wave Motion)

Q16Paper 1PhysicsSingle Correct OptionHard

Work Energy Power

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 1 Physics Q16] A physical system operating under Work Energy Power is analyzed for Vertical Circular Motion with Critical Tension at Zenith. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Work Energy Power)

Q17Paper 1PhysicsSingle Correct OptionMedium

Kinematics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 1 Physics Q17] A physical system operating under Kinematics is analyzed for Relative Motion in 2D River Swimmer Shortest Time vs Shortest Path. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Kinematics)

Q18Paper 1Chemistry (Physical)Single Correct OptionMedium

Coordination Compounds & Qualitative Inorganic Analysis

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 1 Chemistry Q18] Among the following octahedral coordination complexes, which one exhibits the highest crystal field stabilization energy (CFSE) in terms of magnitude of

\Delta_o

and possesses zero unpaired electrons (

n=0

)?

Practice JEE Main Level (Coordination Compounds & Qualitative Inorganic Analysis)

Q19Paper 1Chemistry (Inorganic)One or More Correct (Partial Marking)Hard

Organic Chemistry & Reaction Mechanisms

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 1 Chemistry Q19] Treatment of 2,3-dimethylbutane-2,3-diol (Pinacol) with concentrated sulphuric acid (

H_2SO_4

) at elevated temperature yields 3,3-dimethylbutan-2-one (Pinacolone). Which of the following statements concerning this reaction is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Organic Chemistry & Reaction Mechanisms)

Q20Paper 1Chemistry (Organic)One or More Correct (Partial Marking)Hard

Chemical Kinetics & Radioactivity

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 1 Chemistry Q20] In a detailed investigation of Consecutive First Order Reactions & Steady State Approximation under Chemical Kinetics & Radioactivity, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Chemical Kinetics & Radioactivity)

Q21Paper 1Chemistry (Physical)One or More Correct (Partial Marking)Medium

Thermodynamics & Thermochemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 1 Chemistry Q21] In a detailed investigation of Born-Haber Cycle & Lattice Energy Calculations under Thermodynamics & Thermochemistry, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Thermodynamics & Thermochemistry)

Q22Paper 1Chemistry (Organic)One or More Correct (Partial Marking)Hard

Electrochemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 1 Chemistry Q22] In a detailed investigation of Concentration Cell with Transference & Liquid Junction Potential under Electrochemistry, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Electrochemistry)

Q23Paper 1Chemistry (Inorganic)One or More Correct (Partial Marking)Medium

Chemical & Ionic Equilibrium

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 1 Chemistry Q23] In a detailed investigation of Simultaneous Solubility in Amphoteric Hydroxide Solutions under Chemical & Ionic Equilibrium, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Chemical & Ionic Equilibrium)

Q24Paper 1Chemistry (Physical)One or More Correct (Partial Marking)Hard

Solid State

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 1 Chemistry Q24] In a detailed investigation of Radius Ratio & Octahedral vs Tetrahedral Void Occupancy under Solid State, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Solid State)

Q25Paper 1Chemistry (Inorganic)Numerical Value TypeMedium

Solutions & Colligative Properties

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 1 Chemistry Q25] In a detailed investigation of Van't Hoff Factor in Dimerization and Association Equilibria under Solutions & Colligative Properties, consider the reacting mixture and mechanism:

Practice JEE Main Level (Solutions & Colligative Properties)

Q26Paper 1Chemistry (Organic)Numerical Value TypeHard

p-Block Elements

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 1 Chemistry Q26] In a detailed investigation of Oxyacids of Phosphorus & Silicon Polymers Structure under p-Block Elements, consider the reacting mixture and mechanism:

Practice JEE Main Level (p-Block Elements)

Q27Paper 1Chemistry (Physical)Numerical Value TypeMedium

d- and f-Block Elements

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 1 Chemistry Q27] In a detailed investigation of Lanthanoid Contraction & Separation of Rare Earth Ions under d- and f-Block Elements, consider the reacting mixture and mechanism:

Practice JEE Main Level (d- and f-Block Elements)

Q28Paper 1Chemistry (Organic)Numerical Value TypeHard

Metallurgy & Extraction

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 1 Chemistry Q28] In a detailed investigation of Ellingham Diagram & Thermodynamic Feasibility of Smelting under Metallurgy & Extraction, consider the reacting mixture and mechanism:

Practice JEE Main Level (Metallurgy & Extraction)

Q29Paper 1Chemistry (Inorganic)Numerical Value TypeMedium

Aldehydes, Ketones and Carboxylic Acids

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 1 Chemistry Q29] In a detailed investigation of Intramolecular Aldol & Michael Addition Sequence under Aldehydes, Ketones and Carboxylic Acids, consider the reacting mixture and mechanism:

Practice JEE Main Level (Aldehydes, Ketones and Carboxylic Acids)

Q30Paper 1Chemistry (Physical)Single Correct OptionHard

Aromatic Compounds

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 1 Chemistry Q30] In a detailed investigation of Electrophilic Aromatic Substitution with Directing Groups under Aromatic Compounds, consider the reacting mixture and mechanism:

Practice JEE Main Level (Aromatic Compounds)

Q31Paper 1Chemistry (Inorganic)Single Correct OptionMedium

Amines & Diazonium Salts

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 1 Chemistry Q31] In a detailed investigation of Sandmeyer Reaction vs Gattermann Synthesis Mechanisms under Amines & Diazonium Salts, consider the reacting mixture and mechanism:

Practice JEE Main Level (Amines & Diazonium Salts)

Q32Paper 1Chemistry (Organic)Single Correct OptionHard

Biomolecules & Polymers

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 1 Chemistry Q32] In a detailed investigation of Mutarotation in Glucose & Peptide Linkage Conformation under Biomolecules & Polymers, consider the reacting mixture and mechanism:

Practice JEE Main Level (Biomolecules & Polymers)

Q33Paper 1Chemistry (Physical)Single Correct OptionMedium

Haloalkanes & Haloarenes

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 1 Chemistry Q33] In a detailed investigation of SN1 vs SN2 vs SNi Mechanisms with Stereochemical Inversion under Haloalkanes & Haloarenes, consider the reacting mixture and mechanism:

Practice JEE Main Level (Haloalkanes & Haloarenes)

Q34Paper 1Chemistry (Organic)Single Correct OptionHard

Qualitative Inorganic Salt Analysis

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 1 Chemistry Q34] In a detailed investigation of Chromyl Chloride Test & Brown Ring Complex Formation under Qualitative Inorganic Salt Analysis, consider the reacting mixture and mechanism:

Practice JEE Main Level (Qualitative Inorganic Salt Analysis)

Q35Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Integral Calculus (Definite Integrals & Differential Equations)

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 1 Mathematics Q35] Let

f: (0, \infty) \to \mathbb{R}

be a differentiable function satisfying

f(1) = 1

and

x \int_1^x f(t) dt = (x+1) \int_1^x t f(t) dt

for all

x > 0

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Integral Calculus (Definite Integrals & Differential Equations))

Q36Paper 1MathematicsNumerical Value TypeMedium

Vectors and 3D Geometry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 1 Mathematics Q36] Find the shortest distance between the two skew straight lines

L_1: \vec{r}_1 = (\hat{i} + 2\hat{j} + 3\hat{k}) + \lambda (2\hat{i} + 3\hat{j} + 4\hat{k})

and

L_2: \vec{r}_2 = (2\hat{i} + 4\hat{j} + 5\hat{k}) + \mu (3\hat{i} + 4\hat{j} + 5\hat{k})

. Give the exact distance squared (

d^2

).

Practice JEE Main Level (Vectors and 3D Geometry)

Q37Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Complex Numbers & Quadratic Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 1 Mathematics Q37] Let the mathematical relation governing Geometry of Circles and Apollonius Circles in Complex Plane in Complex Numbers & Quadratic Equations be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Complex Numbers & Quadratic Equations)

Q38Paper 1MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Matrices and Determinants

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 1 Mathematics Q38] Let the mathematical relation governing Cayley-Hamilton Theorem and Inverse of Orthogonal Matrices in Matrices and Determinants be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Matrices and Determinants)

Q39Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Probability & Statistics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 1 Mathematics Q39] Let the mathematical relation governing Bayes Theorem in Multi-Urn Sampling with Replacement in Probability & Statistics be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Probability & Statistics)

Q40Paper 1MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Permutations and Combinations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 1 Mathematics Q40] Let the mathematical relation governing Derangements and Multinomial Distribution Coefficients in Permutations and Combinations be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Permutations and Combinations)

Q41Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Differential Calculus (Continuity & AOD)

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 1 Mathematics Q41] Let the mathematical relation governing Lagrange Mean Value Theorem and Monotonicity Intervals in Differential Calculus (Continuity & AOD) be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Differential Calculus (Continuity & AOD))

Q42Paper 1MathematicsNumerical Value TypeTough / Advanced

Application of Derivatives (Maxima & Minima)

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 1 Mathematics Q42] Let the mathematical relation governing Optimization on Parametric Curves with Constraint Geometry in Application of Derivatives (Maxima & Minima) be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Application of Derivatives (Maxima & Minima))

Q43Paper 1MathematicsNumerical Value TypeHard

Definite Integration

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 1 Mathematics Q43] Let the mathematical relation governing King Rule and Reduction Formula for Trigonometric Powers in Definite Integration be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Definite Integration)

Q44Paper 1MathematicsNumerical Value TypeTough / Advanced

Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 1 Mathematics Q44] Let the mathematical relation governing Bernoulli Differential Equation with Variable Substitution in Differential Equations be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Differential Equations)

Q45Paper 1MathematicsNumerical Value TypeHard

Coordinate Geometry - Parabola

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 1 Mathematics Q45] Let the mathematical relation governing Co-normal Points and Locus of Point of Intersection of Tangents in Coordinate Geometry - Parabola be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Coordinate Geometry - Parabola)

Q46Paper 1MathematicsNumerical Value TypeTough / Advanced

Coordinate Geometry - Ellipse & Hyperbola

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 1 Mathematics Q46] Let the mathematical relation governing Director Circle and Asymptotes of Conjugate Hyperbolas in Coordinate Geometry - Ellipse & Hyperbola be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Coordinate Geometry - Ellipse & Hyperbola)

Q47Paper 1MathematicsSingle Correct OptionHard

Trigonometry & Inverse Trigonometric Functions

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 1 Mathematics Q47] Let the mathematical relation governing Summation of Inverse Trigonometric Series via Telescoping in Trigonometry & Inverse Trigonometric Functions be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Trigonometry & Inverse Trigonometric Functions)

Q48Paper 1MathematicsSingle Correct OptionTough / Advanced

Binomial Theorem

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 1 Mathematics Q48] Let the mathematical relation governing Double Summation and Coefficients of Generalized Multinomial Series in Binomial Theorem be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Binomial Theorem)

Q49Paper 1MathematicsSingle Correct OptionHard

Limits, Continuity and Differentiability

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 1 Mathematics Q49] Let the mathematical relation governing Evaluation of

1^\infty

Indeterminate Form and Squeeze Theorem in Limits, Continuity and Differentiability be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Limits, Continuity and Differentiability)

Q50Paper 1MathematicsSingle Correct OptionTough / Advanced

Functions & Relations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 1 Mathematics Q50] Let the mathematical relation governing Functional Equations and Injective/Surjective Mapping Properties in Functions & Relations be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Functions & Relations)

Q51Paper 1MathematicsSingle Correct OptionHard

Sequences and Series

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 1 Mathematics Q51] Let the mathematical relation governing Arithmetico-Geometric Progression (AGP) and Infinite Sum Convergence in Sequences and Series be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Sequences and Series)

Q1Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 2 Physics Q1] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 2

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q2Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 2 Physics Q2] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 4

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q3Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 2 Physics Q3] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 6

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q4Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 2 Physics Q4] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 8

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q5Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 2 Physics Q5] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 10

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q6Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 2 Physics Q6] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 12

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q7Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 2 Physics Q7] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 14

. Find the exact response:

Q8Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 2 Physics Q8] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 16

. Find the exact response:

Q9Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 2 Physics Q9] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 18

. Find the exact response:

Q10Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 2 Physics Q10] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 20

. Find the exact response:

Q11Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 2 Physics Q11] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 22

. Find the exact response:

Q12Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 2 Physics Q12] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 24

. Find the exact response:

Q13Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 2 Physics Q13] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 26

. Find the exact response:

Q14Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 2 Physics Q14] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 28

. Find the exact response:

Q15Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 2 Physics Q15] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 30

. Find the exact response:

Q16Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 2 Physics Q16] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 32

. Find the exact response:

Q17Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 2 Physics Q17] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 34

. Find the exact response:

Q18Paper 2Chemistry (Physical)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 2 Chemistry Q18] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q19Paper 2Chemistry (Inorganic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 2 Chemistry Q19] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q20Paper 2Chemistry (Organic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 2 Chemistry Q20] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q21Paper 2Chemistry (Physical)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 2 Chemistry Q21] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q22Paper 2Chemistry (Organic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 2 Chemistry Q22] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q23Paper 2Chemistry (Inorganic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 2 Chemistry Q23] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q24Paper 2Chemistry (Physical)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 2 Chemistry Q24] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q25Paper 2Chemistry (Inorganic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 2 Chemistry Q25] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q26Paper 2Chemistry (Organic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 2 Chemistry Q26] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q27Paper 2Chemistry (Physical)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 2 Chemistry Q27] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q28Paper 2Chemistry (Organic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 2 Chemistry Q28] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q29Paper 2Chemistry (Inorganic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 2 Chemistry Q29] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q30Paper 2Chemistry (Physical)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 2 Chemistry Q30] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q31Paper 2Chemistry (Inorganic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 2 Chemistry Q31] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q32Paper 2Chemistry (Organic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 2 Chemistry Q32] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q33Paper 2Chemistry (Physical)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 2 Chemistry Q33] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q34Paper 2Chemistry (Organic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 2 Chemistry Q34] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q35Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 2 Mathematics Q35] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q36Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 2 Mathematics Q36] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q37Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 2 Mathematics Q37] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q38Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 2 Mathematics Q38] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q39Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 2 Mathematics Q39] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q40Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2019 Paper 2 Mathematics Q40] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q41Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 2 Mathematics Q41] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q42Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 2 Mathematics Q42] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q43Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 2 Mathematics Q43] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q44Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 2 Mathematics Q44] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q45Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 2 Mathematics Q45] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q46Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2019 Paper 2 Mathematics Q46] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q47Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 2 Mathematics Q47] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q48Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 2 Mathematics Q48] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q49Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 2 Mathematics Q49] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q50Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 2 Mathematics Q50] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q51Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2019 Paper 2 Mathematics Q51] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q1Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Rotational Motion & Rigid Body Dynamics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 1 Physics Q1] A thin uniform circular disc of mass

M

and radius

R

is placed on a rough horizontal surface with coefficient of friction

\mu

. At time

t=0

, a horizontal impulse

J

is applied at a height

h = \frac{R}{2}

above the center of mass. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Rotational Motion & Rigid Body Dynamics)

Q2Paper 1PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrostatics & Electric Potential

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 1 Physics Q2] A point charge

+q

is located at a distance

d

from the planar boundary of an infinite semi-infinite dielectric medium with dielectric constant

K > 1

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Electrostatics & Electric Potential)

Q3Paper 1PhysicsSingle Correct OptionHard

Thermodynamics & Kinetic Theory

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 1 Physics Q3] One mole of an ideal gas has a molar heat capacity at constant volume that varies with absolute temperature according to

C_V = C_0 + \alpha T

, where

C_0

and

\alpha

are positive constants. The gas undergoes a quasi-static adiabatic process from initial state

(T_1, V_1)

to final state

(T_2, V_2)

. The relation between

T

and

V

is given by:

Practice JEE Main Level (Thermodynamics & Kinetic Theory)

Q4Paper 1PhysicsNumerical Value TypeTough / Advanced

Electromagnetic Induction & Alternating Current

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 1 Physics Q4] A circular wire loop of radius

a = 0.1\text{ m}

and resistance

R = 2\,\Omega

is placed in a uniform magnetic field

B(t) = B_0 \cos(\omega t)

directed perpendicular to the loop, where

B_0 = 1\text{ T}

and

\omega = 100\text{ rad/s}

. If self-inductance of the loop is

L = 0.02\text{ H}

, find the peak magnitude of current (in Amperes) induced in the loop. (Take

\pi \approx 3.14

, calculate to two decimal places).

Practice JEE Main Level (Electromagnetic Induction & Alternating Current)

Q5Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Wave Optics & Interference

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 1 Physics Q5] In a standard YDSE setup with slit separation

d

and screen distance

D

, a transparent thin film of thickness

t

is placed in front of one slit. The refractive index of the film varies along its thickness

y

as

\mu(y) = \mu_0 + \beta y

for

0 \le y \le t

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Wave Optics & Interference)

Q6Paper 1PhysicsSingle Correct OptionHard

Modern Physics & Quantum Mechanics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 1 Physics Q6] A hydrogen-like atom consists of a nucleus of mass

M

and charge

+Z e

and an electron of mass

m_e

and charge

-e

. Taking finite nuclear mass into account via reduced mass

\mu = \frac{m_e M}{m_e + M}

, the Rydberg constant

R_M

for this atom is related to the infinite nuclear mass Rydberg constant

R_\infty

by:

Practice JEE Main Level (Modern Physics & Quantum Mechanics)

Q7Paper 1PhysicsNumerical Value TypeTough / Advanced

Fluid Mechanics & Surface Tension

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 1 Physics Q7] A clean glass capillary tube of internal radius

r = 0.5\text{ mm}

is dipped vertically into water of surface tension

T = 0.075\text{ N/m}

, contact angle

\theta = 0^\circ

, and density

\rho = 1000\text{ kg/m}^3

. What is the equilibrium height

h

(in mm) of the water column in the capillary tube? (Take

g = 10\text{ m/s}^2

).

Practice JEE Main Level (Fluid Mechanics & Surface Tension)

Q8Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Mechanics & Gravitation

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 1 Physics Q8] A physical system operating under Mechanics & Gravitation is analyzed for Kepler Orbit & Angular Momentum in Elliptical Trajectory. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Mechanics & Gravitation)

Q9Paper 1PhysicsOne or More Correct (Partial Marking)Medium

Oscillations & SHM

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 1 Physics Q9] A physical system operating under Oscillations & SHM is analyzed for Coupled Spring Mass System & Normal Modes. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Oscillations & SHM)

Q10Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Magnetic Effects of Current

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 1 Physics Q10] A physical system operating under Magnetic Effects of Current is analyzed for Cyclotron Motion in Crossed Electric and Magnetic Fields. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Magnetic Effects of Current)

Q11Paper 1PhysicsNumerical Value TypeMedium

Ray Optics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 1 Physics Q11] A physical system operating under Ray Optics is analyzed for Refraction through Silvered Prism & Dispersion without Deviation. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Ray Optics)

Q12Paper 1PhysicsNumerical Value TypeHard

Alternating Current

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 1 Physics Q12] A physical system operating under Alternating Current is analyzed for LCR Resonance & Quality Factor Sharpness. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Alternating Current)

Q13Paper 1PhysicsNumerical Value TypeMedium

Semiconductors

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 1 Physics Q13] A physical system operating under Semiconductors is analyzed for Zener Diode Voltage Regulator with Variable Load. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Semiconductors)

Q14Paper 1PhysicsNumerical Value TypeHard

Nuclear Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 1 Physics Q14] A physical system operating under Nuclear Physics is analyzed for Successive Radioactive Decay & Secular Equilibrium. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Nuclear Physics)

Q15Paper 1PhysicsSingle Correct OptionMedium

Wave Motion

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 1 Physics Q15] A physical system operating under Wave Motion is analyzed for Doppler Effect with Reflected Echo from Moving Reflector. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Wave Motion)

Q16Paper 1PhysicsSingle Correct OptionHard

Work Energy Power

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 1 Physics Q16] A physical system operating under Work Energy Power is analyzed for Vertical Circular Motion with Critical Tension at Zenith. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Work Energy Power)

Q17Paper 1PhysicsSingle Correct OptionMedium

Kinematics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 1 Physics Q17] A physical system operating under Kinematics is analyzed for Relative Motion in 2D River Swimmer Shortest Time vs Shortest Path. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Kinematics)

Q18Paper 1Chemistry (Physical)Single Correct OptionMedium

Coordination Compounds & Qualitative Inorganic Analysis

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 1 Chemistry Q18] Among the following octahedral coordination complexes, which one exhibits the highest crystal field stabilization energy (CFSE) in terms of magnitude of

\Delta_o

and possesses zero unpaired electrons (

n=0

)?

Practice JEE Main Level (Coordination Compounds & Qualitative Inorganic Analysis)

Q19Paper 1Chemistry (Inorganic)One or More Correct (Partial Marking)Hard

Organic Chemistry & Reaction Mechanisms

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 1 Chemistry Q19] Treatment of 2,3-dimethylbutane-2,3-diol (Pinacol) with concentrated sulphuric acid (

H_2SO_4

) at elevated temperature yields 3,3-dimethylbutan-2-one (Pinacolone). Which of the following statements concerning this reaction is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Organic Chemistry & Reaction Mechanisms)

Q20Paper 1Chemistry (Organic)One or More Correct (Partial Marking)Hard

Chemical Kinetics & Radioactivity

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 1 Chemistry Q20] In a detailed investigation of Consecutive First Order Reactions & Steady State Approximation under Chemical Kinetics & Radioactivity, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Chemical Kinetics & Radioactivity)

Q21Paper 1Chemistry (Physical)One or More Correct (Partial Marking)Medium

Thermodynamics & Thermochemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 1 Chemistry Q21] In a detailed investigation of Born-Haber Cycle & Lattice Energy Calculations under Thermodynamics & Thermochemistry, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Thermodynamics & Thermochemistry)

Q22Paper 1Chemistry (Organic)One or More Correct (Partial Marking)Hard

Electrochemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 1 Chemistry Q22] In a detailed investigation of Concentration Cell with Transference & Liquid Junction Potential under Electrochemistry, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Electrochemistry)

Q23Paper 1Chemistry (Inorganic)One or More Correct (Partial Marking)Medium

Chemical & Ionic Equilibrium

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 1 Chemistry Q23] In a detailed investigation of Simultaneous Solubility in Amphoteric Hydroxide Solutions under Chemical & Ionic Equilibrium, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Chemical & Ionic Equilibrium)

Q24Paper 1Chemistry (Physical)One or More Correct (Partial Marking)Hard

Solid State

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 1 Chemistry Q24] In a detailed investigation of Radius Ratio & Octahedral vs Tetrahedral Void Occupancy under Solid State, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Solid State)

Q25Paper 1Chemistry (Inorganic)Numerical Value TypeMedium

Solutions & Colligative Properties

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 1 Chemistry Q25] In a detailed investigation of Van't Hoff Factor in Dimerization and Association Equilibria under Solutions & Colligative Properties, consider the reacting mixture and mechanism:

Practice JEE Main Level (Solutions & Colligative Properties)

Q26Paper 1Chemistry (Organic)Numerical Value TypeHard

p-Block Elements

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 1 Chemistry Q26] In a detailed investigation of Oxyacids of Phosphorus & Silicon Polymers Structure under p-Block Elements, consider the reacting mixture and mechanism:

Practice JEE Main Level (p-Block Elements)

Q27Paper 1Chemistry (Physical)Numerical Value TypeMedium

d- and f-Block Elements

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 1 Chemistry Q27] In a detailed investigation of Lanthanoid Contraction & Separation of Rare Earth Ions under d- and f-Block Elements, consider the reacting mixture and mechanism:

Practice JEE Main Level (d- and f-Block Elements)

Q28Paper 1Chemistry (Organic)Numerical Value TypeHard

Metallurgy & Extraction

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 1 Chemistry Q28] In a detailed investigation of Ellingham Diagram & Thermodynamic Feasibility of Smelting under Metallurgy & Extraction, consider the reacting mixture and mechanism:

Practice JEE Main Level (Metallurgy & Extraction)

Q29Paper 1Chemistry (Inorganic)Numerical Value TypeMedium

Aldehydes, Ketones and Carboxylic Acids

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 1 Chemistry Q29] In a detailed investigation of Intramolecular Aldol & Michael Addition Sequence under Aldehydes, Ketones and Carboxylic Acids, consider the reacting mixture and mechanism:

Practice JEE Main Level (Aldehydes, Ketones and Carboxylic Acids)

Q30Paper 1Chemistry (Physical)Single Correct OptionHard

Aromatic Compounds

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 1 Chemistry Q30] In a detailed investigation of Electrophilic Aromatic Substitution with Directing Groups under Aromatic Compounds, consider the reacting mixture and mechanism:

Practice JEE Main Level (Aromatic Compounds)

Q31Paper 1Chemistry (Inorganic)Single Correct OptionMedium

Amines & Diazonium Salts

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 1 Chemistry Q31] In a detailed investigation of Sandmeyer Reaction vs Gattermann Synthesis Mechanisms under Amines & Diazonium Salts, consider the reacting mixture and mechanism:

Practice JEE Main Level (Amines & Diazonium Salts)

Q32Paper 1Chemistry (Organic)Single Correct OptionHard

Biomolecules & Polymers

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 1 Chemistry Q32] In a detailed investigation of Mutarotation in Glucose & Peptide Linkage Conformation under Biomolecules & Polymers, consider the reacting mixture and mechanism:

Practice JEE Main Level (Biomolecules & Polymers)

Q33Paper 1Chemistry (Physical)Single Correct OptionMedium

Haloalkanes & Haloarenes

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 1 Chemistry Q33] In a detailed investigation of SN1 vs SN2 vs SNi Mechanisms with Stereochemical Inversion under Haloalkanes & Haloarenes, consider the reacting mixture and mechanism:

Practice JEE Main Level (Haloalkanes & Haloarenes)

Q34Paper 1Chemistry (Organic)Single Correct OptionHard

Qualitative Inorganic Salt Analysis

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 1 Chemistry Q34] In a detailed investigation of Chromyl Chloride Test & Brown Ring Complex Formation under Qualitative Inorganic Salt Analysis, consider the reacting mixture and mechanism:

Practice JEE Main Level (Qualitative Inorganic Salt Analysis)

Q35Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Integral Calculus (Definite Integrals & Differential Equations)

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 1 Mathematics Q35] Let

f: (0, \infty) \to \mathbb{R}

be a differentiable function satisfying

f(1) = 1

and

x \int_1^x f(t) dt = (x+1) \int_1^x t f(t) dt

for all

x > 0

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Integral Calculus (Definite Integrals & Differential Equations))

Q36Paper 1MathematicsNumerical Value TypeMedium

Vectors and 3D Geometry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 1 Mathematics Q36] Find the shortest distance between the two skew straight lines

L_1: \vec{r}_1 = (\hat{i} + 2\hat{j} + 3\hat{k}) + \lambda (2\hat{i} + 3\hat{j} + 4\hat{k})

and

L_2: \vec{r}_2 = (2\hat{i} + 4\hat{j} + 5\hat{k}) + \mu (3\hat{i} + 4\hat{j} + 5\hat{k})

. Give the exact distance squared (

d^2

).

Practice JEE Main Level (Vectors and 3D Geometry)

Q37Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Complex Numbers & Quadratic Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 1 Mathematics Q37] Let the mathematical relation governing Geometry of Circles and Apollonius Circles in Complex Plane in Complex Numbers & Quadratic Equations be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Complex Numbers & Quadratic Equations)

Q38Paper 1MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Matrices and Determinants

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 1 Mathematics Q38] Let the mathematical relation governing Cayley-Hamilton Theorem and Inverse of Orthogonal Matrices in Matrices and Determinants be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Matrices and Determinants)

Q39Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Probability & Statistics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 1 Mathematics Q39] Let the mathematical relation governing Bayes Theorem in Multi-Urn Sampling with Replacement in Probability & Statistics be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Probability & Statistics)

Q40Paper 1MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Permutations and Combinations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 1 Mathematics Q40] Let the mathematical relation governing Derangements and Multinomial Distribution Coefficients in Permutations and Combinations be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Permutations and Combinations)

Q41Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Differential Calculus (Continuity & AOD)

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 1 Mathematics Q41] Let the mathematical relation governing Lagrange Mean Value Theorem and Monotonicity Intervals in Differential Calculus (Continuity & AOD) be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Differential Calculus (Continuity & AOD))

Q42Paper 1MathematicsNumerical Value TypeTough / Advanced

Application of Derivatives (Maxima & Minima)

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 1 Mathematics Q42] Let the mathematical relation governing Optimization on Parametric Curves with Constraint Geometry in Application of Derivatives (Maxima & Minima) be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Application of Derivatives (Maxima & Minima))

Q43Paper 1MathematicsNumerical Value TypeHard

Definite Integration

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 1 Mathematics Q43] Let the mathematical relation governing King Rule and Reduction Formula for Trigonometric Powers in Definite Integration be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Definite Integration)

Q44Paper 1MathematicsNumerical Value TypeTough / Advanced

Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 1 Mathematics Q44] Let the mathematical relation governing Bernoulli Differential Equation with Variable Substitution in Differential Equations be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Differential Equations)

Q45Paper 1MathematicsNumerical Value TypeHard

Coordinate Geometry - Parabola

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 1 Mathematics Q45] Let the mathematical relation governing Co-normal Points and Locus of Point of Intersection of Tangents in Coordinate Geometry - Parabola be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Coordinate Geometry - Parabola)

Q46Paper 1MathematicsNumerical Value TypeTough / Advanced

Coordinate Geometry - Ellipse & Hyperbola

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 1 Mathematics Q46] Let the mathematical relation governing Director Circle and Asymptotes of Conjugate Hyperbolas in Coordinate Geometry - Ellipse & Hyperbola be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Coordinate Geometry - Ellipse & Hyperbola)

Q47Paper 1MathematicsSingle Correct OptionHard

Trigonometry & Inverse Trigonometric Functions

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 1 Mathematics Q47] Let the mathematical relation governing Summation of Inverse Trigonometric Series via Telescoping in Trigonometry & Inverse Trigonometric Functions be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Trigonometry & Inverse Trigonometric Functions)

Q48Paper 1MathematicsSingle Correct OptionTough / Advanced

Binomial Theorem

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 1 Mathematics Q48] Let the mathematical relation governing Double Summation and Coefficients of Generalized Multinomial Series in Binomial Theorem be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Binomial Theorem)

Q49Paper 1MathematicsSingle Correct OptionHard

Limits, Continuity and Differentiability

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 1 Mathematics Q49] Let the mathematical relation governing Evaluation of

1^\infty

Indeterminate Form and Squeeze Theorem in Limits, Continuity and Differentiability be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Limits, Continuity and Differentiability)

Q50Paper 1MathematicsSingle Correct OptionTough / Advanced

Functions & Relations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 1 Mathematics Q50] Let the mathematical relation governing Functional Equations and Injective/Surjective Mapping Properties in Functions & Relations be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Functions & Relations)

Q51Paper 1MathematicsSingle Correct OptionHard

Sequences and Series

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 1 Mathematics Q51] Let the mathematical relation governing Arithmetico-Geometric Progression (AGP) and Infinite Sum Convergence in Sequences and Series be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Sequences and Series)

Q1Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 2 Physics Q1] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 2

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q2Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 2 Physics Q2] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 4

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q3Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 2 Physics Q3] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 6

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q4Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 2 Physics Q4] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 8

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q5Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 2 Physics Q5] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 10

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q6Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 2 Physics Q6] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 12

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q7Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 2 Physics Q7] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 14

. Find the exact response:

Q8Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 2 Physics Q8] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 16

. Find the exact response:

Q9Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 2 Physics Q9] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 18

. Find the exact response:

Q10Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 2 Physics Q10] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 20

. Find the exact response:

Q11Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 2 Physics Q11] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 22

. Find the exact response:

Q12Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 2 Physics Q12] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 24

. Find the exact response:

Q13Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 2 Physics Q13] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 26

. Find the exact response:

Q14Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 2 Physics Q14] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 28

. Find the exact response:

Q15Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 2 Physics Q15] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 30

. Find the exact response:

Q16Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 2 Physics Q16] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 32

. Find the exact response:

Q17Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 2 Physics Q17] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 34

. Find the exact response:

Q18Paper 2Chemistry (Physical)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 2 Chemistry Q18] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q19Paper 2Chemistry (Inorganic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 2 Chemistry Q19] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q20Paper 2Chemistry (Organic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 2 Chemistry Q20] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q21Paper 2Chemistry (Physical)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 2 Chemistry Q21] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q22Paper 2Chemistry (Organic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 2 Chemistry Q22] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q23Paper 2Chemistry (Inorganic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 2 Chemistry Q23] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q24Paper 2Chemistry (Physical)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 2 Chemistry Q24] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q25Paper 2Chemistry (Inorganic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 2 Chemistry Q25] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q26Paper 2Chemistry (Organic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 2 Chemistry Q26] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q27Paper 2Chemistry (Physical)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 2 Chemistry Q27] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q28Paper 2Chemistry (Organic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 2 Chemistry Q28] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q29Paper 2Chemistry (Inorganic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 2 Chemistry Q29] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q30Paper 2Chemistry (Physical)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 2 Chemistry Q30] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q31Paper 2Chemistry (Inorganic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 2 Chemistry Q31] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q32Paper 2Chemistry (Organic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 2 Chemistry Q32] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q33Paper 2Chemistry (Physical)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 2 Chemistry Q33] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q34Paper 2Chemistry (Organic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 2 Chemistry Q34] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q35Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 2 Mathematics Q35] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q36Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 2 Mathematics Q36] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q37Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 2 Mathematics Q37] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q38Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 2 Mathematics Q38] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q39Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 2 Mathematics Q39] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q40Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2018 Paper 2 Mathematics Q40] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q41Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 2 Mathematics Q41] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q42Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 2 Mathematics Q42] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q43Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 2 Mathematics Q43] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q44Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 2 Mathematics Q44] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q45Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 2 Mathematics Q45] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q46Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2018 Paper 2 Mathematics Q46] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q47Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 2 Mathematics Q47] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q48Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 2 Mathematics Q48] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q49Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 2 Mathematics Q49] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q50Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 2 Mathematics Q50] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q51Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2018 Paper 2 Mathematics Q51] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q1Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Rotational Motion & Rigid Body Dynamics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 1 Physics Q1] A thin uniform circular disc of mass

M

and radius

R

is placed on a rough horizontal surface with coefficient of friction

\mu

. At time

t=0

, a horizontal impulse

J

is applied at a height

h = \frac{R}{2}

above the center of mass. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Rotational Motion & Rigid Body Dynamics)

Q2Paper 1PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrostatics & Electric Potential

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 1 Physics Q2] A point charge

+q

is located at a distance

d

from the planar boundary of an infinite semi-infinite dielectric medium with dielectric constant

K > 1

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Electrostatics & Electric Potential)

Q3Paper 1PhysicsSingle Correct OptionHard

Thermodynamics & Kinetic Theory

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 1 Physics Q3] One mole of an ideal gas has a molar heat capacity at constant volume that varies with absolute temperature according to

C_V = C_0 + \alpha T

, where

C_0

and

\alpha

are positive constants. The gas undergoes a quasi-static adiabatic process from initial state

(T_1, V_1)

to final state

(T_2, V_2)

. The relation between

T

and

V

is given by:

Practice JEE Main Level (Thermodynamics & Kinetic Theory)

Q4Paper 1PhysicsNumerical Value TypeTough / Advanced

Electromagnetic Induction & Alternating Current

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 1 Physics Q4] A circular wire loop of radius

a = 0.1\text{ m}

and resistance

R = 2\,\Omega

is placed in a uniform magnetic field

B(t) = B_0 \cos(\omega t)

directed perpendicular to the loop, where

B_0 = 1\text{ T}

and

\omega = 100\text{ rad/s}

. If self-inductance of the loop is

L = 0.02\text{ H}

, find the peak magnitude of current (in Amperes) induced in the loop. (Take

\pi \approx 3.14

, calculate to two decimal places).

Practice JEE Main Level (Electromagnetic Induction & Alternating Current)

Q5Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Wave Optics & Interference

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 1 Physics Q5] In a standard YDSE setup with slit separation

d

and screen distance

D

, a transparent thin film of thickness

t

is placed in front of one slit. The refractive index of the film varies along its thickness

y

as

\mu(y) = \mu_0 + \beta y

for

0 \le y \le t

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Wave Optics & Interference)

Q6Paper 1PhysicsSingle Correct OptionHard

Modern Physics & Quantum Mechanics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 1 Physics Q6] A hydrogen-like atom consists of a nucleus of mass

M

and charge

+Z e

and an electron of mass

m_e

and charge

-e

. Taking finite nuclear mass into account via reduced mass

\mu = \frac{m_e M}{m_e + M}

, the Rydberg constant

R_M

for this atom is related to the infinite nuclear mass Rydberg constant

R_\infty

by:

Practice JEE Main Level (Modern Physics & Quantum Mechanics)

Q7Paper 1PhysicsNumerical Value TypeTough / Advanced

Fluid Mechanics & Surface Tension

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 1 Physics Q7] A clean glass capillary tube of internal radius

r = 0.5\text{ mm}

is dipped vertically into water of surface tension

T = 0.075\text{ N/m}

, contact angle

\theta = 0^\circ

, and density

\rho = 1000\text{ kg/m}^3

. What is the equilibrium height

h

(in mm) of the water column in the capillary tube? (Take

g = 10\text{ m/s}^2

).

Practice JEE Main Level (Fluid Mechanics & Surface Tension)

Q8Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Mechanics & Gravitation

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 1 Physics Q8] A physical system operating under Mechanics & Gravitation is analyzed for Kepler Orbit & Angular Momentum in Elliptical Trajectory. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Mechanics & Gravitation)

Q9Paper 1PhysicsOne or More Correct (Partial Marking)Medium

Oscillations & SHM

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 1 Physics Q9] A physical system operating under Oscillations & SHM is analyzed for Coupled Spring Mass System & Normal Modes. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Oscillations & SHM)

Q10Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Magnetic Effects of Current

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 1 Physics Q10] A physical system operating under Magnetic Effects of Current is analyzed for Cyclotron Motion in Crossed Electric and Magnetic Fields. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Magnetic Effects of Current)

Q11Paper 1PhysicsNumerical Value TypeMedium

Ray Optics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 1 Physics Q11] A physical system operating under Ray Optics is analyzed for Refraction through Silvered Prism & Dispersion without Deviation. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Ray Optics)

Q12Paper 1PhysicsNumerical Value TypeHard

Alternating Current

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 1 Physics Q12] A physical system operating under Alternating Current is analyzed for LCR Resonance & Quality Factor Sharpness. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Alternating Current)

Q13Paper 1PhysicsNumerical Value TypeMedium

Semiconductors

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 1 Physics Q13] A physical system operating under Semiconductors is analyzed for Zener Diode Voltage Regulator with Variable Load. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Semiconductors)

Q14Paper 1PhysicsNumerical Value TypeHard

Nuclear Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 1 Physics Q14] A physical system operating under Nuclear Physics is analyzed for Successive Radioactive Decay & Secular Equilibrium. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Nuclear Physics)

Q15Paper 1PhysicsSingle Correct OptionMedium

Wave Motion

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 1 Physics Q15] A physical system operating under Wave Motion is analyzed for Doppler Effect with Reflected Echo from Moving Reflector. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Wave Motion)

Q16Paper 1PhysicsSingle Correct OptionHard

Work Energy Power

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 1 Physics Q16] A physical system operating under Work Energy Power is analyzed for Vertical Circular Motion with Critical Tension at Zenith. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Work Energy Power)

Q17Paper 1PhysicsSingle Correct OptionMedium

Kinematics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 1 Physics Q17] A physical system operating under Kinematics is analyzed for Relative Motion in 2D River Swimmer Shortest Time vs Shortest Path. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Kinematics)

Q18Paper 1Chemistry (Physical)Single Correct OptionMedium

Coordination Compounds & Qualitative Inorganic Analysis

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 1 Chemistry Q18] Among the following octahedral coordination complexes, which one exhibits the highest crystal field stabilization energy (CFSE) in terms of magnitude of

\Delta_o

and possesses zero unpaired electrons (

n=0

)?

Practice JEE Main Level (Coordination Compounds & Qualitative Inorganic Analysis)

Q19Paper 1Chemistry (Inorganic)One or More Correct (Partial Marking)Hard

Organic Chemistry & Reaction Mechanisms

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 1 Chemistry Q19] Treatment of 2,3-dimethylbutane-2,3-diol (Pinacol) with concentrated sulphuric acid (

H_2SO_4

) at elevated temperature yields 3,3-dimethylbutan-2-one (Pinacolone). Which of the following statements concerning this reaction is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Organic Chemistry & Reaction Mechanisms)

Q20Paper 1Chemistry (Organic)One or More Correct (Partial Marking)Hard

Chemical Kinetics & Radioactivity

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 1 Chemistry Q20] In a detailed investigation of Consecutive First Order Reactions & Steady State Approximation under Chemical Kinetics & Radioactivity, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Chemical Kinetics & Radioactivity)

Q21Paper 1Chemistry (Physical)One or More Correct (Partial Marking)Medium

Thermodynamics & Thermochemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 1 Chemistry Q21] In a detailed investigation of Born-Haber Cycle & Lattice Energy Calculations under Thermodynamics & Thermochemistry, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Thermodynamics & Thermochemistry)

Q22Paper 1Chemistry (Organic)One or More Correct (Partial Marking)Hard

Electrochemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 1 Chemistry Q22] In a detailed investigation of Concentration Cell with Transference & Liquid Junction Potential under Electrochemistry, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Electrochemistry)

Q23Paper 1Chemistry (Inorganic)One or More Correct (Partial Marking)Medium

Chemical & Ionic Equilibrium

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 1 Chemistry Q23] In a detailed investigation of Simultaneous Solubility in Amphoteric Hydroxide Solutions under Chemical & Ionic Equilibrium, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Chemical & Ionic Equilibrium)

Q24Paper 1Chemistry (Physical)One or More Correct (Partial Marking)Hard

Solid State

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 1 Chemistry Q24] In a detailed investigation of Radius Ratio & Octahedral vs Tetrahedral Void Occupancy under Solid State, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Solid State)

Q25Paper 1Chemistry (Inorganic)Numerical Value TypeMedium

Solutions & Colligative Properties

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 1 Chemistry Q25] In a detailed investigation of Van't Hoff Factor in Dimerization and Association Equilibria under Solutions & Colligative Properties, consider the reacting mixture and mechanism:

Practice JEE Main Level (Solutions & Colligative Properties)

Q26Paper 1Chemistry (Organic)Numerical Value TypeHard

p-Block Elements

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 1 Chemistry Q26] In a detailed investigation of Oxyacids of Phosphorus & Silicon Polymers Structure under p-Block Elements, consider the reacting mixture and mechanism:

Practice JEE Main Level (p-Block Elements)

Q27Paper 1Chemistry (Physical)Numerical Value TypeMedium

d- and f-Block Elements

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 1 Chemistry Q27] In a detailed investigation of Lanthanoid Contraction & Separation of Rare Earth Ions under d- and f-Block Elements, consider the reacting mixture and mechanism:

Practice JEE Main Level (d- and f-Block Elements)

Q28Paper 1Chemistry (Organic)Numerical Value TypeHard

Metallurgy & Extraction

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 1 Chemistry Q28] In a detailed investigation of Ellingham Diagram & Thermodynamic Feasibility of Smelting under Metallurgy & Extraction, consider the reacting mixture and mechanism:

Practice JEE Main Level (Metallurgy & Extraction)

Q29Paper 1Chemistry (Inorganic)Numerical Value TypeMedium

Aldehydes, Ketones and Carboxylic Acids

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 1 Chemistry Q29] In a detailed investigation of Intramolecular Aldol & Michael Addition Sequence under Aldehydes, Ketones and Carboxylic Acids, consider the reacting mixture and mechanism:

Practice JEE Main Level (Aldehydes, Ketones and Carboxylic Acids)

Q30Paper 1Chemistry (Physical)Single Correct OptionHard

Aromatic Compounds

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 1 Chemistry Q30] In a detailed investigation of Electrophilic Aromatic Substitution with Directing Groups under Aromatic Compounds, consider the reacting mixture and mechanism:

Practice JEE Main Level (Aromatic Compounds)

Q31Paper 1Chemistry (Inorganic)Single Correct OptionMedium

Amines & Diazonium Salts

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 1 Chemistry Q31] In a detailed investigation of Sandmeyer Reaction vs Gattermann Synthesis Mechanisms under Amines & Diazonium Salts, consider the reacting mixture and mechanism:

Practice JEE Main Level (Amines & Diazonium Salts)

Q32Paper 1Chemistry (Organic)Single Correct OptionHard

Biomolecules & Polymers

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 1 Chemistry Q32] In a detailed investigation of Mutarotation in Glucose & Peptide Linkage Conformation under Biomolecules & Polymers, consider the reacting mixture and mechanism:

Practice JEE Main Level (Biomolecules & Polymers)

Q33Paper 1Chemistry (Physical)Single Correct OptionMedium

Haloalkanes & Haloarenes

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 1 Chemistry Q33] In a detailed investigation of SN1 vs SN2 vs SNi Mechanisms with Stereochemical Inversion under Haloalkanes & Haloarenes, consider the reacting mixture and mechanism:

Practice JEE Main Level (Haloalkanes & Haloarenes)

Q34Paper 1Chemistry (Organic)Single Correct OptionHard

Qualitative Inorganic Salt Analysis

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 1 Chemistry Q34] In a detailed investigation of Chromyl Chloride Test & Brown Ring Complex Formation under Qualitative Inorganic Salt Analysis, consider the reacting mixture and mechanism:

Practice JEE Main Level (Qualitative Inorganic Salt Analysis)

Q35Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Integral Calculus (Definite Integrals & Differential Equations)

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 1 Mathematics Q35] Let

f: (0, \infty) \to \mathbb{R}

be a differentiable function satisfying

f(1) = 1

and

x \int_1^x f(t) dt = (x+1) \int_1^x t f(t) dt

for all

x > 0

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Integral Calculus (Definite Integrals & Differential Equations))

Q36Paper 1MathematicsNumerical Value TypeMedium

Vectors and 3D Geometry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 1 Mathematics Q36] Find the shortest distance between the two skew straight lines

L_1: \vec{r}_1 = (\hat{i} + 2\hat{j} + 3\hat{k}) + \lambda (2\hat{i} + 3\hat{j} + 4\hat{k})

and

L_2: \vec{r}_2 = (2\hat{i} + 4\hat{j} + 5\hat{k}) + \mu (3\hat{i} + 4\hat{j} + 5\hat{k})

. Give the exact distance squared (

d^2

).

Practice JEE Main Level (Vectors and 3D Geometry)

Q37Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Complex Numbers & Quadratic Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 1 Mathematics Q37] Let the mathematical relation governing Geometry of Circles and Apollonius Circles in Complex Plane in Complex Numbers & Quadratic Equations be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Complex Numbers & Quadratic Equations)

Q38Paper 1MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Matrices and Determinants

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 1 Mathematics Q38] Let the mathematical relation governing Cayley-Hamilton Theorem and Inverse of Orthogonal Matrices in Matrices and Determinants be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Matrices and Determinants)

Q39Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Probability & Statistics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 1 Mathematics Q39] Let the mathematical relation governing Bayes Theorem in Multi-Urn Sampling with Replacement in Probability & Statistics be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Probability & Statistics)

Q40Paper 1MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Permutations and Combinations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 1 Mathematics Q40] Let the mathematical relation governing Derangements and Multinomial Distribution Coefficients in Permutations and Combinations be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Permutations and Combinations)

Q41Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Differential Calculus (Continuity & AOD)

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 1 Mathematics Q41] Let the mathematical relation governing Lagrange Mean Value Theorem and Monotonicity Intervals in Differential Calculus (Continuity & AOD) be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Differential Calculus (Continuity & AOD))

Q42Paper 1MathematicsNumerical Value TypeTough / Advanced

Application of Derivatives (Maxima & Minima)

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 1 Mathematics Q42] Let the mathematical relation governing Optimization on Parametric Curves with Constraint Geometry in Application of Derivatives (Maxima & Minima) be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Application of Derivatives (Maxima & Minima))

Q43Paper 1MathematicsNumerical Value TypeHard

Definite Integration

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 1 Mathematics Q43] Let the mathematical relation governing King Rule and Reduction Formula for Trigonometric Powers in Definite Integration be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Definite Integration)

Q44Paper 1MathematicsNumerical Value TypeTough / Advanced

Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 1 Mathematics Q44] Let the mathematical relation governing Bernoulli Differential Equation with Variable Substitution in Differential Equations be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Differential Equations)

Q45Paper 1MathematicsNumerical Value TypeHard

Coordinate Geometry - Parabola

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 1 Mathematics Q45] Let the mathematical relation governing Co-normal Points and Locus of Point of Intersection of Tangents in Coordinate Geometry - Parabola be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Coordinate Geometry - Parabola)

Q46Paper 1MathematicsNumerical Value TypeTough / Advanced

Coordinate Geometry - Ellipse & Hyperbola

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 1 Mathematics Q46] Let the mathematical relation governing Director Circle and Asymptotes of Conjugate Hyperbolas in Coordinate Geometry - Ellipse & Hyperbola be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Coordinate Geometry - Ellipse & Hyperbola)

Q47Paper 1MathematicsSingle Correct OptionHard

Trigonometry & Inverse Trigonometric Functions

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 1 Mathematics Q47] Let the mathematical relation governing Summation of Inverse Trigonometric Series via Telescoping in Trigonometry & Inverse Trigonometric Functions be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Trigonometry & Inverse Trigonometric Functions)

Q48Paper 1MathematicsSingle Correct OptionTough / Advanced

Binomial Theorem

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 1 Mathematics Q48] Let the mathematical relation governing Double Summation and Coefficients of Generalized Multinomial Series in Binomial Theorem be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Binomial Theorem)

Q49Paper 1MathematicsSingle Correct OptionHard

Limits, Continuity and Differentiability

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 1 Mathematics Q49] Let the mathematical relation governing Evaluation of

1^\infty

Indeterminate Form and Squeeze Theorem in Limits, Continuity and Differentiability be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Limits, Continuity and Differentiability)

Q50Paper 1MathematicsSingle Correct OptionTough / Advanced

Functions & Relations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 1 Mathematics Q50] Let the mathematical relation governing Functional Equations and Injective/Surjective Mapping Properties in Functions & Relations be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Functions & Relations)

Q51Paper 1MathematicsSingle Correct OptionHard

Sequences and Series

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 1 Mathematics Q51] Let the mathematical relation governing Arithmetico-Geometric Progression (AGP) and Infinite Sum Convergence in Sequences and Series be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Sequences and Series)

Q1Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 2 Physics Q1] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 2

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q2Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 2 Physics Q2] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 4

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q3Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 2 Physics Q3] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 6

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q4Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 2 Physics Q4] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 8

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q5Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 2 Physics Q5] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 10

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q6Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 2 Physics Q6] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 12

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q7Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 2 Physics Q7] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 14

. Find the exact response:

Q8Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 2 Physics Q8] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 16

. Find the exact response:

Q9Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 2 Physics Q9] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 18

. Find the exact response:

Q10Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 2 Physics Q10] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 20

. Find the exact response:

Q11Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 2 Physics Q11] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 22

. Find the exact response:

Q12Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 2 Physics Q12] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 24

. Find the exact response:

Q13Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 2 Physics Q13] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 26

. Find the exact response:

Q14Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 2 Physics Q14] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 28

. Find the exact response:

Q15Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 2 Physics Q15] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 30

. Find the exact response:

Q16Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 2 Physics Q16] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 32

. Find the exact response:

Q17Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 2 Physics Q17] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 34

. Find the exact response:

Q18Paper 2Chemistry (Physical)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 2 Chemistry Q18] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q19Paper 2Chemistry (Inorganic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 2 Chemistry Q19] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q20Paper 2Chemistry (Organic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 2 Chemistry Q20] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q21Paper 2Chemistry (Physical)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 2 Chemistry Q21] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q22Paper 2Chemistry (Organic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 2 Chemistry Q22] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q23Paper 2Chemistry (Inorganic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 2 Chemistry Q23] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q24Paper 2Chemistry (Physical)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 2 Chemistry Q24] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q25Paper 2Chemistry (Inorganic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 2 Chemistry Q25] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q26Paper 2Chemistry (Organic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 2 Chemistry Q26] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q27Paper 2Chemistry (Physical)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 2 Chemistry Q27] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q28Paper 2Chemistry (Organic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 2 Chemistry Q28] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q29Paper 2Chemistry (Inorganic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 2 Chemistry Q29] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q30Paper 2Chemistry (Physical)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 2 Chemistry Q30] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q31Paper 2Chemistry (Inorganic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 2 Chemistry Q31] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q32Paper 2Chemistry (Organic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 2 Chemistry Q32] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q33Paper 2Chemistry (Physical)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 2 Chemistry Q33] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q34Paper 2Chemistry (Organic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 2 Chemistry Q34] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q35Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 2 Mathematics Q35] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q36Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 2 Mathematics Q36] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q37Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 2 Mathematics Q37] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q38Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 2 Mathematics Q38] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q39Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 2 Mathematics Q39] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q40Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2017 Paper 2 Mathematics Q40] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q41Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 2 Mathematics Q41] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q42Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 2 Mathematics Q42] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q43Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 2 Mathematics Q43] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q44Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 2 Mathematics Q44] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q45Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 2 Mathematics Q45] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q46Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2017 Paper 2 Mathematics Q46] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q47Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 2 Mathematics Q47] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q48Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 2 Mathematics Q48] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q49Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 2 Mathematics Q49] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q50Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 2 Mathematics Q50] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q51Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2017 Paper 2 Mathematics Q51] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q1Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Rotational Motion & Rigid Body Dynamics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 1 Physics Q1] A thin uniform circular disc of mass

M

and radius

R

is placed on a rough horizontal surface with coefficient of friction

\mu

. At time

t=0

, a horizontal impulse

J

is applied at a height

h = \frac{R}{2}

above the center of mass. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Rotational Motion & Rigid Body Dynamics)

Q2Paper 1PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrostatics & Electric Potential

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 1 Physics Q2] A point charge

+q

is located at a distance

d

from the planar boundary of an infinite semi-infinite dielectric medium with dielectric constant

K > 1

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Electrostatics & Electric Potential)

Q3Paper 1PhysicsSingle Correct OptionHard

Thermodynamics & Kinetic Theory

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 1 Physics Q3] One mole of an ideal gas has a molar heat capacity at constant volume that varies with absolute temperature according to

C_V = C_0 + \alpha T

, where

C_0

and

\alpha

are positive constants. The gas undergoes a quasi-static adiabatic process from initial state

(T_1, V_1)

to final state

(T_2, V_2)

. The relation between

T

and

V

is given by:

Practice JEE Main Level (Thermodynamics & Kinetic Theory)

Q4Paper 1PhysicsNumerical Value TypeTough / Advanced

Electromagnetic Induction & Alternating Current

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 1 Physics Q4] A circular wire loop of radius

a = 0.1\text{ m}

and resistance

R = 2\,\Omega

is placed in a uniform magnetic field

B(t) = B_0 \cos(\omega t)

directed perpendicular to the loop, where

B_0 = 1\text{ T}

and

\omega = 100\text{ rad/s}

. If self-inductance of the loop is

L = 0.02\text{ H}

, find the peak magnitude of current (in Amperes) induced in the loop. (Take

\pi \approx 3.14

, calculate to two decimal places).

Practice JEE Main Level (Electromagnetic Induction & Alternating Current)

Q5Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Wave Optics & Interference

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 1 Physics Q5] In a standard YDSE setup with slit separation

d

and screen distance

D

, a transparent thin film of thickness

t

is placed in front of one slit. The refractive index of the film varies along its thickness

y

as

\mu(y) = \mu_0 + \beta y

for

0 \le y \le t

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Wave Optics & Interference)

Q6Paper 1PhysicsSingle Correct OptionHard

Modern Physics & Quantum Mechanics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 1 Physics Q6] A hydrogen-like atom consists of a nucleus of mass

M

and charge

+Z e

and an electron of mass

m_e

and charge

-e

. Taking finite nuclear mass into account via reduced mass

\mu = \frac{m_e M}{m_e + M}

, the Rydberg constant

R_M

for this atom is related to the infinite nuclear mass Rydberg constant

R_\infty

by:

Practice JEE Main Level (Modern Physics & Quantum Mechanics)

Q7Paper 1PhysicsNumerical Value TypeTough / Advanced

Fluid Mechanics & Surface Tension

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 1 Physics Q7] A clean glass capillary tube of internal radius

r = 0.5\text{ mm}

is dipped vertically into water of surface tension

T = 0.075\text{ N/m}

, contact angle

\theta = 0^\circ

, and density

\rho = 1000\text{ kg/m}^3

. What is the equilibrium height

h

(in mm) of the water column in the capillary tube? (Take

g = 10\text{ m/s}^2

).

Practice JEE Main Level (Fluid Mechanics & Surface Tension)

Q8Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Mechanics & Gravitation

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 1 Physics Q8] A physical system operating under Mechanics & Gravitation is analyzed for Kepler Orbit & Angular Momentum in Elliptical Trajectory. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Mechanics & Gravitation)

Q9Paper 1PhysicsOne or More Correct (Partial Marking)Medium

Oscillations & SHM

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 1 Physics Q9] A physical system operating under Oscillations & SHM is analyzed for Coupled Spring Mass System & Normal Modes. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Oscillations & SHM)

Q10Paper 1PhysicsOne or More Correct (Partial Marking)Hard

Magnetic Effects of Current

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 1 Physics Q10] A physical system operating under Magnetic Effects of Current is analyzed for Cyclotron Motion in Crossed Electric and Magnetic Fields. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Magnetic Effects of Current)

Q11Paper 1PhysicsNumerical Value TypeMedium

Ray Optics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 1 Physics Q11] A physical system operating under Ray Optics is analyzed for Refraction through Silvered Prism & Dispersion without Deviation. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Ray Optics)

Q12Paper 1PhysicsNumerical Value TypeHard

Alternating Current

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 1 Physics Q12] A physical system operating under Alternating Current is analyzed for LCR Resonance & Quality Factor Sharpness. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Alternating Current)

Q13Paper 1PhysicsNumerical Value TypeMedium

Semiconductors

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 1 Physics Q13] A physical system operating under Semiconductors is analyzed for Zener Diode Voltage Regulator with Variable Load. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Semiconductors)

Q14Paper 1PhysicsNumerical Value TypeHard

Nuclear Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 1 Physics Q14] A physical system operating under Nuclear Physics is analyzed for Successive Radioactive Decay & Secular Equilibrium. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Nuclear Physics)

Q15Paper 1PhysicsSingle Correct OptionMedium

Wave Motion

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 1 Physics Q15] A physical system operating under Wave Motion is analyzed for Doppler Effect with Reflected Echo from Moving Reflector. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Wave Motion)

Q16Paper 1PhysicsSingle Correct OptionHard

Work Energy Power

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 1 Physics Q16] A physical system operating under Work Energy Power is analyzed for Vertical Circular Motion with Critical Tension at Zenith. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Work Energy Power)

Q17Paper 1PhysicsSingle Correct OptionMedium

Kinematics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 1 Physics Q17] A physical system operating under Kinematics is analyzed for Relative Motion in 2D River Swimmer Shortest Time vs Shortest Path. If the governing parameter is evaluated under standard boundary conditions with exact constraints:

Practice JEE Main Level (Kinematics)

Q18Paper 1Chemistry (Physical)Single Correct OptionMedium

Coordination Compounds & Qualitative Inorganic Analysis

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 1 Chemistry Q18] Among the following octahedral coordination complexes, which one exhibits the highest crystal field stabilization energy (CFSE) in terms of magnitude of

\Delta_o

and possesses zero unpaired electrons (

n=0

)?

Practice JEE Main Level (Coordination Compounds & Qualitative Inorganic Analysis)

Q19Paper 1Chemistry (Inorganic)One or More Correct (Partial Marking)Hard

Organic Chemistry & Reaction Mechanisms

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 1 Chemistry Q19] Treatment of 2,3-dimethylbutane-2,3-diol (Pinacol) with concentrated sulphuric acid (

H_2SO_4

) at elevated temperature yields 3,3-dimethylbutan-2-one (Pinacolone). Which of the following statements concerning this reaction is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Organic Chemistry & Reaction Mechanisms)

Q20Paper 1Chemistry (Organic)One or More Correct (Partial Marking)Hard

Chemical Kinetics & Radioactivity

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 1 Chemistry Q20] In a detailed investigation of Consecutive First Order Reactions & Steady State Approximation under Chemical Kinetics & Radioactivity, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Chemical Kinetics & Radioactivity)

Q21Paper 1Chemistry (Physical)One or More Correct (Partial Marking)Medium

Thermodynamics & Thermochemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 1 Chemistry Q21] In a detailed investigation of Born-Haber Cycle & Lattice Energy Calculations under Thermodynamics & Thermochemistry, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Thermodynamics & Thermochemistry)

Q22Paper 1Chemistry (Organic)One or More Correct (Partial Marking)Hard

Electrochemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 1 Chemistry Q22] In a detailed investigation of Concentration Cell with Transference & Liquid Junction Potential under Electrochemistry, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Electrochemistry)

Q23Paper 1Chemistry (Inorganic)One or More Correct (Partial Marking)Medium

Chemical & Ionic Equilibrium

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 1 Chemistry Q23] In a detailed investigation of Simultaneous Solubility in Amphoteric Hydroxide Solutions under Chemical & Ionic Equilibrium, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Chemical & Ionic Equilibrium)

Q24Paper 1Chemistry (Physical)One or More Correct (Partial Marking)Hard

Solid State

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 1 Chemistry Q24] In a detailed investigation of Radius Ratio & Octahedral vs Tetrahedral Void Occupancy under Solid State, consider the reacting mixture and mechanism:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Solid State)

Q25Paper 1Chemistry (Inorganic)Numerical Value TypeMedium

Solutions & Colligative Properties

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 1 Chemistry Q25] In a detailed investigation of Van't Hoff Factor in Dimerization and Association Equilibria under Solutions & Colligative Properties, consider the reacting mixture and mechanism:

Practice JEE Main Level (Solutions & Colligative Properties)

Q26Paper 1Chemistry (Organic)Numerical Value TypeHard

p-Block Elements

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 1 Chemistry Q26] In a detailed investigation of Oxyacids of Phosphorus & Silicon Polymers Structure under p-Block Elements, consider the reacting mixture and mechanism:

Practice JEE Main Level (p-Block Elements)

Q27Paper 1Chemistry (Physical)Numerical Value TypeMedium

d- and f-Block Elements

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 1 Chemistry Q27] In a detailed investigation of Lanthanoid Contraction & Separation of Rare Earth Ions under d- and f-Block Elements, consider the reacting mixture and mechanism:

Practice JEE Main Level (d- and f-Block Elements)

Q28Paper 1Chemistry (Organic)Numerical Value TypeHard

Metallurgy & Extraction

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 1 Chemistry Q28] In a detailed investigation of Ellingham Diagram & Thermodynamic Feasibility of Smelting under Metallurgy & Extraction, consider the reacting mixture and mechanism:

Practice JEE Main Level (Metallurgy & Extraction)

Q29Paper 1Chemistry (Inorganic)Numerical Value TypeMedium

Aldehydes, Ketones and Carboxylic Acids

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 1 Chemistry Q29] In a detailed investigation of Intramolecular Aldol & Michael Addition Sequence under Aldehydes, Ketones and Carboxylic Acids, consider the reacting mixture and mechanism:

Practice JEE Main Level (Aldehydes, Ketones and Carboxylic Acids)

Q30Paper 1Chemistry (Physical)Single Correct OptionHard

Aromatic Compounds

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 1 Chemistry Q30] In a detailed investigation of Electrophilic Aromatic Substitution with Directing Groups under Aromatic Compounds, consider the reacting mixture and mechanism:

Practice JEE Main Level (Aromatic Compounds)

Q31Paper 1Chemistry (Inorganic)Single Correct OptionMedium

Amines & Diazonium Salts

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 1 Chemistry Q31] In a detailed investigation of Sandmeyer Reaction vs Gattermann Synthesis Mechanisms under Amines & Diazonium Salts, consider the reacting mixture and mechanism:

Practice JEE Main Level (Amines & Diazonium Salts)

Q32Paper 1Chemistry (Organic)Single Correct OptionHard

Biomolecules & Polymers

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 1 Chemistry Q32] In a detailed investigation of Mutarotation in Glucose & Peptide Linkage Conformation under Biomolecules & Polymers, consider the reacting mixture and mechanism:

Practice JEE Main Level (Biomolecules & Polymers)

Q33Paper 1Chemistry (Physical)Single Correct OptionMedium

Haloalkanes & Haloarenes

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 1 Chemistry Q33] In a detailed investigation of SN1 vs SN2 vs SNi Mechanisms with Stereochemical Inversion under Haloalkanes & Haloarenes, consider the reacting mixture and mechanism:

Practice JEE Main Level (Haloalkanes & Haloarenes)

Q34Paper 1Chemistry (Organic)Single Correct OptionHard

Qualitative Inorganic Salt Analysis

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 1 Chemistry Q34] In a detailed investigation of Chromyl Chloride Test & Brown Ring Complex Formation under Qualitative Inorganic Salt Analysis, consider the reacting mixture and mechanism:

Practice JEE Main Level (Qualitative Inorganic Salt Analysis)

Q35Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Integral Calculus (Definite Integrals & Differential Equations)

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 1 Mathematics Q35] Let

f: (0, \infty) \to \mathbb{R}

be a differentiable function satisfying

f(1) = 1

and

x \int_1^x f(t) dt = (x+1) \int_1^x t f(t) dt

for all

x > 0

. Which of the following statements is/are CORRECT?

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Integral Calculus (Definite Integrals & Differential Equations))

Q36Paper 1MathematicsNumerical Value TypeMedium

Vectors and 3D Geometry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 1 Mathematics Q36] Find the shortest distance between the two skew straight lines

L_1: \vec{r}_1 = (\hat{i} + 2\hat{j} + 3\hat{k}) + \lambda (2\hat{i} + 3\hat{j} + 4\hat{k})

and

L_2: \vec{r}_2 = (2\hat{i} + 4\hat{j} + 5\hat{k}) + \mu (3\hat{i} + 4\hat{j} + 5\hat{k})

. Give the exact distance squared (

d^2

).

Practice JEE Main Level (Vectors and 3D Geometry)

Q37Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Complex Numbers & Quadratic Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 1 Mathematics Q37] Let the mathematical relation governing Geometry of Circles and Apollonius Circles in Complex Plane in Complex Numbers & Quadratic Equations be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Complex Numbers & Quadratic Equations)

Q38Paper 1MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Matrices and Determinants

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 1 Mathematics Q38] Let the mathematical relation governing Cayley-Hamilton Theorem and Inverse of Orthogonal Matrices in Matrices and Determinants be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Matrices and Determinants)

Q39Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Probability & Statistics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 1 Mathematics Q39] Let the mathematical relation governing Bayes Theorem in Multi-Urn Sampling with Replacement in Probability & Statistics be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Probability & Statistics)

Q40Paper 1MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Permutations and Combinations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 1 Mathematics Q40] Let the mathematical relation governing Derangements and Multinomial Distribution Coefficients in Permutations and Combinations be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Permutations and Combinations)

Q41Paper 1MathematicsOne or More Correct (Partial Marking)Hard

Differential Calculus (Continuity & AOD)

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 1 Mathematics Q41] Let the mathematical relation governing Lagrange Mean Value Theorem and Monotonicity Intervals in Differential Calculus (Continuity & AOD) be defined over its maximal domain. Evaluate the mathematical properties:

Select one or more options, then click "Submit Choices":

Practice JEE Main Level (Differential Calculus (Continuity & AOD))

Q42Paper 1MathematicsNumerical Value TypeTough / Advanced

Application of Derivatives (Maxima & Minima)

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 1 Mathematics Q42] Let the mathematical relation governing Optimization on Parametric Curves with Constraint Geometry in Application of Derivatives (Maxima & Minima) be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Application of Derivatives (Maxima & Minima))

Q43Paper 1MathematicsNumerical Value TypeHard

Definite Integration

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 1 Mathematics Q43] Let the mathematical relation governing King Rule and Reduction Formula for Trigonometric Powers in Definite Integration be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Definite Integration)

Q44Paper 1MathematicsNumerical Value TypeTough / Advanced

Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 1 Mathematics Q44] Let the mathematical relation governing Bernoulli Differential Equation with Variable Substitution in Differential Equations be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Differential Equations)

Q45Paper 1MathematicsNumerical Value TypeHard

Coordinate Geometry - Parabola

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 1 Mathematics Q45] Let the mathematical relation governing Co-normal Points and Locus of Point of Intersection of Tangents in Coordinate Geometry - Parabola be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Coordinate Geometry - Parabola)

Q46Paper 1MathematicsNumerical Value TypeTough / Advanced

Coordinate Geometry - Ellipse & Hyperbola

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 1 Mathematics Q46] Let the mathematical relation governing Director Circle and Asymptotes of Conjugate Hyperbolas in Coordinate Geometry - Ellipse & Hyperbola be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Coordinate Geometry - Ellipse & Hyperbola)

Q47Paper 1MathematicsSingle Correct OptionHard

Trigonometry & Inverse Trigonometric Functions

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 1 Mathematics Q47] Let the mathematical relation governing Summation of Inverse Trigonometric Series via Telescoping in Trigonometry & Inverse Trigonometric Functions be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Trigonometry & Inverse Trigonometric Functions)

Q48Paper 1MathematicsSingle Correct OptionTough / Advanced

Binomial Theorem

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 1 Mathematics Q48] Let the mathematical relation governing Double Summation and Coefficients of Generalized Multinomial Series in Binomial Theorem be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Binomial Theorem)

Q49Paper 1MathematicsSingle Correct OptionHard

Limits, Continuity and Differentiability

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 1 Mathematics Q49] Let the mathematical relation governing Evaluation of

1^\infty

Indeterminate Form and Squeeze Theorem in Limits, Continuity and Differentiability be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Limits, Continuity and Differentiability)

Q50Paper 1MathematicsSingle Correct OptionTough / Advanced

Functions & Relations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 1 Mathematics Q50] Let the mathematical relation governing Functional Equations and Injective/Surjective Mapping Properties in Functions & Relations be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Functions & Relations)

Q51Paper 1MathematicsSingle Correct OptionHard

Sequences and Series

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 1 Mathematics Q51] Let the mathematical relation governing Arithmetico-Geometric Progression (AGP) and Infinite Sum Convergence in Sequences and Series be defined over its maximal domain. Evaluate the mathematical properties:

Practice JEE Main Level (Sequences and Series)

Q1Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 2 Physics Q1] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 2

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q2Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 2 Physics Q2] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 4

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q3Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 2 Physics Q3] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 6

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q4Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 2 Physics Q4] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 8

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q5Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 2 Physics Q5] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 10

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q6Paper 2PhysicsOne or More Correct (Partial Marking)Tough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 2 Physics Q6] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 12

. Find the exact response:

Select one or more options, then click "Submit Choices":

Q7Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 2 Physics Q7] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 14

. Find the exact response:

Q8Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 2 Physics Q8] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 16

. Find the exact response:

Q9Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 2 Physics Q9] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 18

. Find the exact response:

Q10Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 2 Physics Q10] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 20

. Find the exact response:

Q11Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 2 Physics Q11] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 22

. Find the exact response:

Q12Paper 2PhysicsNumerical Value TypeTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 2 Physics Q12] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 24

. Find the exact response:

Q13Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 2 Physics Q13] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 26

. Find the exact response:

Q14Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 2 Physics Q14] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 28

. Find the exact response:

Q15Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 2 Physics Q15] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 30

. Find the exact response:

Q16Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 2 Physics Q16] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 32

. Find the exact response:

Q17Paper 2PhysicsSingle Correct OptionTough / Advanced

Electrodynamics & Advanced Physics

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 2 Physics Q17] An advanced experimental setup investigates electromagnetic radiation and thermodynamics under non-inertial frame transformation with parameter

\alpha = 34

. Find the exact response:

Q18Paper 2Chemistry (Physical)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 2 Chemistry Q18] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q19Paper 2Chemistry (Inorganic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 2 Chemistry Q19] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q20Paper 2Chemistry (Organic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 2 Chemistry Q20] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q21Paper 2Chemistry (Physical)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 2 Chemistry Q21] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q22Paper 2Chemistry (Organic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 2 Chemistry Q22] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q23Paper 2Chemistry (Inorganic)One or More Correct (Partial Marking)Tough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 2 Chemistry Q23] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Select one or more options, then click "Submit Choices":

Q24Paper 2Chemistry (Physical)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 2 Chemistry Q24] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q25Paper 2Chemistry (Inorganic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 2 Chemistry Q25] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q26Paper 2Chemistry (Organic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 2 Chemistry Q26] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q27Paper 2Chemistry (Physical)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 2 Chemistry Q27] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q28Paper 2Chemistry (Organic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 2 Chemistry Q28] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q29Paper 2Chemistry (Inorganic)Numerical Value TypeTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 2 Chemistry Q29] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q30Paper 2Chemistry (Physical)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 2 Chemistry Q30] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q31Paper 2Chemistry (Inorganic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 2 Chemistry Q31] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q32Paper 2Chemistry (Organic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 2 Chemistry Q32] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q33Paper 2Chemistry (Physical)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 2 Chemistry Q33] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q34Paper 2Chemistry (Organic)Single Correct OptionTough / Advanced

Advanced Organic & Inorganic Chemistry

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 2 Chemistry Q34] An enantiopure compound undergoes multi-step stereoselective synthesis involving organolithium reagent followed by acid-catalyzed cyclization:

Q35Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 2 Mathematics Q35] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q36Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 2 Mathematics Q36] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q37Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 2 Mathematics Q37] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q38Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 2 Mathematics Q38] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q39Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 2 Mathematics Q39] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q40Paper 2MathematicsOne or More Correct (Partial Marking)Tough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • -2 Negative Marks • Partial Marking EnabledSection 2 (One or More Correct Option)

[JEE Advanced 2016 Paper 2 Mathematics Q40] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Select one or more options, then click "Submit Choices":

Q41Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 2 Mathematics Q41] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q42Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 2 Mathematics Q42] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q43Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 2 Mathematics Q43] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q44Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 2 Mathematics Q44] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q45Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 2 Mathematics Q45] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q46Paper 2MathematicsNumerical Value TypeTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +4 Full Marks • 0 Negative Marks Section 3 (Numerical Value / Decimal Type)

[JEE Advanced 2016 Paper 2 Mathematics Q46] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q47Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 2 Mathematics Q47] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q48Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 2 Mathematics Q48] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q49Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 2 Mathematics Q49] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q50Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 2 Mathematics Q50] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

Q51Paper 2MathematicsSingle Correct OptionTough / Advanced

Advanced Calculus & Differential Equations

Scoring Scheme: +3 Full Marks • -1 Negative Marks Section 1 (Single Correct Option)

[JEE Advanced 2016 Paper 2 Mathematics Q51] Let a family of orthogonal trajectories be defined by the second order nonlinear differential equation

y'' + (y')^2 + y = 0

. Evaluate the analytical solution properties:

JEE Advanced Chapter-Wise Previous Year Questions

Matching Questions (1020 Questions)

Browse Top High-Yield Advanced Chapters